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3 years ago

Write an equation in slope-intercept form for each graph shown. Please help!!!!!!!

Mathematics

2 answers:

dmitriy555 [2]3 years ago

8 0

I can help! As you may know y = mx+b is our slope-intercept equation, so let's plug some numbers into where they need to be.

The easiest part is finding B (the y-intercept) which is -3. Now, our equation is y = mx+(-3) or, as we will properly write it, y = mx-3

Let's find the slope (m) now! Let's take the first coordinate given (0, -3) and count the rise over the run that takes us to the next coordinate (2, 1)

Rise (going up) is four, and the run (across) is two. Making our slope 4/2, which is an improper fraction, so let's simplify it to 2. Now, we have our "m,"

That's all you need for this equation, since the y and x are left as they are.

y = 2x-3 is your answer

stiv31 [10]3 years ago

3 0

Answer:

y = 2x-3

Step-by-step explanation:

We have 2 points so we can find the slope

m = (y2-y1)/(x2-x1)

= (1--3)/(2-0)

= (1+3)/(2-0)

=4/2

= 2

The y intercept (where x=0) is -3

We can use the slope intercept form of the equation

y= mx+b where m is the slope and b is the y intercept

y = 2x-3

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Can someone please help me with this question

cricket20 [7]

Answer:

B, E

Step-by-step explanation:

It can be helpful to factor the first two terms:

f(x) = x^2(x -7) +36

This can make it easier to evaluate the function for different values of x.

The answer choices suggest you need to know whether f(5) and f(-14) match the values given here.

f(5) = 5^2(5 -7) +36 = -50 +36 = -14 . . . . matches choice B (and E)

f(-14) = (-14)^2(-14-7) +36 = -21(196) +36 . . . . <em>does not match</em> choice A (or D)

The one remaining answer choice we need to consider is C. If we look at f(0) for this equation, we find it is (-5)(-10) +14 = 64, which <em>does not match</em> f(0) = 36 for the function given in the problem statement.

The only true answer choices are B and E.

_____

The remainder theorem tells you that f(a) = the remainder from f(x)/(x -a).

8 0

4 years ago

Anyone know the answer to all of them added together

Evgesh-ka [11]

Answer:

13x + 14

Step-by-step explanation:

5x + 6 + 3x = 8x + 6.

8x + 6 + x + 1 + x + 1 + 2= 10x + 10

10x + 10 + (2²)(i think) = 10x + 14

10x + 14 + 3x = 13x + 14

final answer

3 0

3 years ago

Read 2 more answers

Write a coordinate proof for the following statement: Any triangle ABC formed so that vertex C is on the perpendicular bisector

AnnyKZ [126]

Answer:

Answer is contained in explanation.

Step-by-step explanation:

Description of visual:

I started with the first picture. This is a picture of triangle ABC.

Now I'm going to draw a line segment from vertex C such that it is a perpendicular bisector of AB.

Proof:

CM is a perpendicular bisectors of AB is a given.

From this we can concluded by definition of perpendicular angles that angle AMC and angle BMC are right angles.

Since angles AMC and BMC are right angles, then they are congruent to each other.

By the definition of bisector and since CM bisects AB, then AM is congruent to MB.

By the reflexive property, we have that CM is congruent to CM.

We can conclude the two triangles, triangle CMA and CMB, are congruent by SAS Postulate.

Since triangles CMA and CMB are congruent, we can conclude that their corresponding parts are congruent.

Since their corresponding parts are congruent, then we now know that side CA and side CB are congruent.

Since two sides of the triangle ABC are congruent to each other, namely side CA and side CB, then the triangle ABC is an isosceles triangle.

Setup for coordinate geometry proof:

M is the midpoint of AB since CM is a bisector of AB.

Since M is the midpoint of AB, then M is located at the coordinates $(\frac{0+b}{2},\frac{0+0}{2})=(\frac{b}{2},0)$ .

We found this point such that the length AM is equal to the length MB.

That is, the distance between A and M is the same as the distance between M and B.

Let's check.

$AM=\sqrt{(\frac{b}{2}-0)^2+(0-0)^2}$

$AM=\sqrt{(\frac{b}{2})^2+0}$

$AM=\sqrt{\frac{b^2}{4}}$

$AM=\frac{\sqrt{b^2}}{\sqrt{4}}$

$AM=\frac{b}{2}$

$MB=\sqrt{(b-\frac{b}{2})^2+(0-0)^2}$

$MB=\sqrt{(\frac{b}{2})^2+0}$

$MB=\sqrt{\frac{b^2}{4}}$

$MB=\frac{\sqrt{b^2}}{\sqrt{4}}$

$MB=\frac{b}{2}$

We have confirmed that AM=MB.

(Based on the picture, we could have taken a slightly easier route to calculate the distance between M and A, then the distance between B and M. They are both a horizontal distance. So $MB=b-\frac{b}{2}=\frac{b}{2}$ where as $AM=\frac{b}{2}-0=\frac{b}{2}$ .)

Now we also want to assume that the line segment CM is perpendicular to AB. I have drawn the base of the triangle on the x-axis so a vertical line would be perpendicular to it. Also this would make point $C=(c,d)=(\frac{b}{2},d)$ . The $y$ -coordinate is $d$ because we don't know how high above the $x$ -axis the point $C$ is.