12 POINTS PLS HELP ASAP Find the length of the missing side.

The Census Bureau's Current Population Survey shows that 28% of individuals, ages 25 and older, have completed four years of col

gizmo_the_mogwai [7]

Answer:

19.35% probability that five will have completed four years of college

Step-by-step explanation:

For each individual chosen, there are only two possible outcomes. Either they have completed fourr years of college, or they have not. The probability of an adult completing four years of college is independent of any other adult. So the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

28% of individuals

This means that $p = 0.25$

For a sample of 15 individuals, ages 25 and older, what is the probability that five will have completed four years of college?

This is P(X = 5) when n = 15. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 5) = C_{15,5}.(0.28)^{5}.(0.72)^{10} = 0.1935$

19.35% probability that five will have completed four years of college

5 0

3 years ago

The square of a number is 12 less than 7 times the number. What is the number?

hjlf

Answer:

The number is either 3 or 4

Explanation:

Assume that the number we are looking for is x

The square of the number would be x²

7 times the number would be 7x

We are given that:

square of the number (x²) is 12 less than 7 times the number (7x)

Translating this into an equation, we would have:

x² = 7x - 12

Rearranging the quadratic equation:

x² - 7x + 12 = 0

Now, we factor the equation:

(x-4)(x-3) = 0

This means that:

either x-4 = 0 ..................> x = 4

or x-3 = 0 ........................> x = 3

Let's check if any of the solutions is an extrovert:

For x = 3 .............> (3)² = 7(3) - 12 .........> 9 = 21 - 12 .......> 9 = 9 .......> not extrovert

For x = 4 .............> (4)² = 7(4) - 12 .........> 16 = 28 - 12 .....> 16 = 16 ....> not extrovert

Since we have no restrictions on the number, therefore, both solutions would be accepted

Hope this helps :)

7 0

3 years ago

Which statements are true about the circle shown?

CaHeK987 [17]

Answer:

Among the five statements,statement 1 and 4 are true for the circle shown.

Step-by-step explanation:

Given:

An image is attached here.

A circle with radius = 15.4 m

We ave to find the diameter,circumference and relationship between the two.

Formula to be used:

⇒ Diameter of a circle = 2r

⇒ Circumference = 2πr

Lets find the values.

Diameter = $2r=2(15.4) = 30.8$ m
Circumference = $2\pi r =2(3.14)(15.4)=96.7$ m
Relationship = $\frac{circumference}{diameter}$ $=$ $\frac{96.7}{6}$ $=3.1$

We can say that a little more than 3 diameters could be wrapped around the circle.

From the drop down our choices are.

The diameter of the circle is 30.8 m.
The approximate circumference of the circle ,rounded to the nearest tenth is 96.7 m.

Option 1 and 4 are the right choices.

8 0

3 years ago

Solve 10/6 + 3/6- 5/6 mentally

Alinara [238K]

Answer:

4/3

Step-by-step explanation:

6 0

3 years ago

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Hi guys, can anyone help me with this triple integral? Many thanks:)

Crank

Another triple integral. We're integrating over the interior of the sphere

$x^2+y^2+z^2=2^2$

Let's do the outer integral over z. z stays within the sphere so it goes from -2 to 2.

For the middle integral we have

$y^2=4-x^2-z^2$

x is the inner integral so at this point we conservatively say its zero. That means y goes from $-\sqrt{4-z^2}$ and $+\sqrt{4-z^2}$

Similarly the inner integral x goes between $\pm-\sqrt{4-y^2-z^2}$

So we rewrite the integral

$\displaystyle \int_{-2}^{2} \int_{-\sqrt{4-z^2}}^{\sqrt{4-z^2}} \int_{-\sqrt{4-y^2-z^2}}^{\sqrt{4-y^2-z^2}} (x^2+xy+y^2)dx \; dy \; dz$

Let's work on the inner one,

$\displaystyle\int_{-\sqrt{4-y^2-z^2}}^{\sqrt{4-y^2-z^2}} (x^2+xy+y^2)dz$

There's no z in the integrand, so we treat it as a constant.

$=(x^2+xy+y^2)z \bigg|_{z=-\sqrt{4-y^2-z^2}}^{z=\sqrt{4-y^2-z^2}}$

So the middle integral is

$\displaystyle\int_{-\sqrt{4-z^2}}^{\sqrt{4-z^2}}2(x^2+xy+y^2)\sqrt{4-y^2-z^2} \ dy$

I gotta go so I'll stop here, sorry.

7 0

3 years ago

Read 2 more answers