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Norma-Jean [14]
3 years ago
14

Write the equation Y=mx+b Not just the rate of change

Mathematics
1 answer:
Andreas93 [3]3 years ago
8 0

Answer:

y=2/5x+8/5

Step-by-step explanation:

so say you plot a graph of rain against the hours the gradient would be the rate of change and the information given as your points and the gradient

now to get an equation of a straight line use one of your points eg(1,2) and the gradient or rate of change mine was 0.4

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Express your answer as a monomial...<br>(6a^2b)(-7a^4b^7)
Arte-miy333 [17]
I hope this helps you


6. (-7).a^2+4.b^1+7

-42.a^6.b^8
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3 years ago
Please help with question 2-6! no one wants to help me out
Zanzabum

Answer:

OMGGGGG I remmeber this :,) But sadly I failed math so sorry :((

Step-by-step explanation:

5 0
3 years ago
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PLEASE HELP ASAP!!! CORRECT ANSWERS ONLY PLEASE!!!
RUDIKE [14]

Jackie wants to keep her total work time <em>under </em>20 hours, so we can set up a rough inequality right away:

(work time in hours) < 20

Now, it's going to take here 1/2 = 0.5 hours to finish each necklace, an 1 hour to finish each bracelet, so if she's making x necklaces, it'll take her 0.5x hours to make all of them, and if she's making y bracelets, it'll take her 1y = y hours to finish those. Putting the two together, it'll take her 0.5x + y hours altogether to make the necklaces and bracelets. Putting that together with our first inequality, we get the final inequality

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4 0
3 years ago
The number of messages arriving at a multiplexer is a Poisson random variable with mean 15 messages/second. Use the central limi
Mila [183]

Answer:

0.048 is the probability that more than 950 message arrive in one minute.

Step-by-step explanation:

We are given the following information in the question:

The number of messages arriving at a multiplexer is a Poisson random variable with mean 15 messages/second.

Let X be the number of messages arriving at a multiplexer.

Mean = 15

For poison distribution,

Mean = Variance = 15

\text{Standard Deviation} = \sqrt{\text{Variance}} = \sqrt{15} = 3.872

From central limit theorem, we have:

z = \displaystyle\frac{x-n\mu}{\sigma\sqrt{n}}

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= 1 - P(z \leq 1.667)

Calculation the value from standard normal z table, we have,  

P(x > 950) = 1 - 0.952 = 0.048

0.048 is the probability that more than 950 message arrive in one minute.

3 0
3 years ago
Find the coordinates of the other endpoint when you are given the midpoint (point M) and one of the endpoints (point P). P = (5,
Rus_ich [418]
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(11,-2)
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3 years ago
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