The last one is the correct answer!! nothing that is dilated can be congruent to another triangle.
Answer:
2cosAcos2A, 4sinAcos^2A
Step-by-step explanation:
cos3A+cosA
2cos((3A+A)/2)cos((3A-A)/2)
2cos(4A/2)cos(2A/2)
2cosAcos2A
sin3A+sinA
2sin((3A+A)/2)cos((3A-A)/2)
2sin(4A/2)cos(2A/2)
2sin2AcosA
4sinAcos^2A
Answer:
the answer is 80
Step-by-step explanation:
hope this helps
can i get braineist pls
No, a cubic equation can not have three complex roots. This is because it turns twice and one end goes to positive infinity and one end goes to negative infinity. Thus, one of these MUST cross the x-axis at some point, meaning y = 0 and a real root exists.
Yes, a cubic equation can have three real roots if it cuts the x-axis three times.
