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3 years ago

How to solve x^4+4x-1=0 ? ...?

Mathematics

1 answer:

Crank3 years ago

7 0

Using the Quadratic formula

x^4 = (x^2)^2

hence

(x^2)^2 + 4x +(-1) = 0

ax^2=1(x^2)^2

bx = 4(x)

c=(-1)

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