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3 years ago

How many solutions exist for the system of equations graphed below? 3 2 54 -3 -2 -1 1 1

Mathematics

1 answer:

Dafna11 [192]3 years ago

8 0

Answer:

Step-by-step explanation:

One solution if they intersect (which is the case), and zero if they are parallel and apart, and infinite if they are parallel and coincident, two lines piled on top of each other.

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In △ABC, AB = 13.2m,

luda_lava [24]

Answer:

(i) ∠ABH = 14.5°

(ii) The length of AH = 4.6 m

Step-by-step explanation:

To solve the problem, we will follow the steps below;

(i)Finding ∠ABH

first lets find <HBC

<BHC + <HBC + <BCH = 180° (Sum of interior angle in a polygon)

46° + <HBC + 90 = 180°

<HBC+ 136° = 180°

subtract 136 from both-side of the equation

<HBC+ 136° - 136° = 180° -136°

<HBC = 44°

lets find <ABC

To do that, we need to first find <BAC

Using the sine rule

$\frac{sin A}{a}$ = $\frac{sin C}{c}$

A = ?

a=6.9

C=90

c=13.2

$\frac{sin A}{6.9}$ = $\frac{sin 90}{13.2}$

sin A = 6.9 sin 90 /13.2

sinA = 0.522727

A = sin⁻¹ ( 0.522727)

A ≈ 31.5 °

<BAC = 31.5°

<BAC + <ABC + <BCA = 180° (sum of interior angle of a triangle)

31.5° +<ABC + 90° = 180°

<ABC + 121.5° = 180°

subtract 121.5° from both-side of the equation

<ABC + 121.5° - 121.5° = 180° - 121.5°

<ABC = 58.5°

<ABH = <ABC - <HBC

=58.5° - 44°

=14.5°

∠ABH = 14.5°

(ii) Finding the length of AH

To find length AH, we need to first find ∠AHB

<AHB + <BHC = 180° ( angle on a straight line)

<AHB + 46° = 180°

subtract 46° from both-side of the equation

<AHB + 46°- 46° = 180° - 46°

<AHB = 134°

Using sine rule,

$\frac{sin 134}{13.2}$ = $\frac{sin 14.5}{AH}$

AH = 13.2 sin 14.5 / sin 134

AH≈4.6 m

length AH = 4.6 m

8 0

3 years ago

Help 8th grade math need answers quick

stepladder [879]

Answer:

A few examples:

0. 0

1. Undefined

2. -3/5

3. Undefined

...

7. 493

8. 5/2

....

Learn how to find the slope below for the other problems.

Step-by-step explanation:

Slope is the rate of change for a linear function. It is found by subtracting the y values of two point on the line and dividing that difference by the difference of the x values of the points.

It can also be found using the formula y=mx+b known as the slope intercept form.

Here are a few examples:

0. This is a horizontal line which always has slope 0.

1. This is a vertical line which always has slope undefined.

2. Find two points that cross through a grid line intersection The line appears to cross them at (5,3) and (0,6). Count the unit squares between the two by counting up 3 and over to the left 5. Because it is left it is negative. The slope is -3/5

3. To find the slope, use the slope formula:

$\frac{y_2-y_1}{x_2-x_1}=\frac{6--4}{-2--2}=\frac{6+4}{-2+2}=\frac{10}{0}=undefined$