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2 years ago

Madelyn is knitting a scarf for a holiday gift. So far, it's 4.5 centimeters long. She plans to

Mathematics

1 answer:

olchik [2.2K]2 years ago

7 0

In order to make the question true the length should be 45cm not 4.5 cm , Solving accordingly

Let nights be x
Rate of change=5cm

The equation is

y=45-5x

As 45 is base amount we used it as y intercect

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If F(x)=4x-1 and g(x)=x^2+7, what is g(f(x))

VashaNatasha [74]

Answer

$g(f(x)) = = 16 {x}^{2} - 8x + 8$

step by step Explanation

The functions given are

$f (x)= 4x- 1$

$g(x)= {x}^{2} + 7$

We want to find:

$g(f (x))= g( 4x- 1)$

This implies that

$g(f (x))= ( (4x- 1)^{2} + 7)$

Let us now simplify

$( {a - b)}^{2} = {a}^{2} -2ab + {b}^{2}$

This implies that

$( (4x- 1)^{2} + 7) =( {(4x)}^{2} - 2(4x) \times 1 + 1$

Combine the terms to get,

$= 16 {x}^{2} - 8x + 1 + 7$

$= 16 {x}^{2} - 8x + 8$

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3 years ago

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zysi [14]

Answer:

Step-by-step explanation:

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3 years ago

Let G be a connnectde graph with n vertices and m edges. supposed also that m = n. prove that G contains exactly one cycle

ElenaW [278]

Answer:

Contradiction

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Suppose that G has more than one cycle and let C be one of the cycles of G, if we remove one of the edges of C from G, then by our supposition the new graph G' would have a cycle. However, the number of edges of G' is equal to m-1=n-1 and G' has the same vertices of G, which means that n is the number of vertices of G. Therefore, the number of edges of G' is equal to the number of vertices of G' minus 1, which tells us that G' is a tree (it has no cycles), and so we get a contradiction.

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3 years ago

I need to find the parent function and compare and contrast the domain and range of the parent function.

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3 years ago

Stacy is selling tickets for the school play. She has a total of 200 seats available, and there will be two types of tickets off

Ganezh [65]

She sold 74 child tickets and 126 adult tickets

Step-by-step explanation:

Stacy is selling tickets for the school play

She has a total of 200 seats available, and there will be two types of tickets offered, child and adult tickets
She sold each child ticket for $6 , each adult ticket for $10 , and made a total of $1704

We need to find how many of each ticket she sold

Assume that x is the number of child tickets and y is the number of the adult tickets

∵ She has a total of 200 seats available

∵ She sold x child tickets

∵ She sold y adult tickets

- Add x and y, then equate the sum by 200

∴ x + y = 200 ⇒ (1)

∵ She sold each child ticket for $6

∵ She sold each adult ticket for $10

∵ She made a total of $1704

- Multiply x by 6 and y by 10, then add the products and

equate them by 1704

∴ 6x + 10y = 1704 ⇒ (2)

Now we have a system of equation to solve it

Multiply equation (1) by -10 to eliminate y

∵ -10x - 10y = -2000 ⇒ (3)

- Add equations (2) and (3) to find x

∴ -4x = -296

- Divide both sides by -4

∴ x = 74

- Substitute the value of x in equation (1) to find y

∵ 74 + y = 200

- Subtract 74 from both sides

∴ y = 126

She sold 74 child tickets and 126 adult tickets

Learn more:

You can learn more about the system of equations in brainly.com/question/2115716

#LearnwithBrainly

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3 years ago