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Bingel [31]
4 years ago
5

Which is most likely to cause confusion, hinder thinking, and prevent quick access to resources in a study environment? phones c

lutter noise laptops
phones
clutter
noise
laptops
Computers and Technology
2 answers:
Lerok [7]4 years ago
6 0

Answer:

clutter

Explanation:

edge 2020

OverLord2011 [107]4 years ago
3 0
Clutter will cause the most problems when you are trying to study because <span>If you’re unable to get through the material clogging up your </span>neural<span> networks, so the theory goes, you’ll be slower and less efficient in processing information. As a result, you’ll be incapacitated when it comes to short-term memory tasks, and even in longer-range mental exercises when you have to come up with information you should know, such as names of people, that you can no longer find within your disorganized repository of knowledge.

Hope this helps, 

kwrob</span>
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Write a code that calculates the Greatest Common Divisor (GCD) of two positive integers (user-defined inputs). Include an except
STALIN [3.7K]

Answer:

<em>This program is written using Java programming language</em>

import java.util.*;

public class calcGcd

{

   public static void main (String [] args)

   {

       int num1, num2;

       Scanner input = new Scanner(System.in);

       //Input two integers

       num1 = input.nextInt();

       num2 = input.nextInt();

       //Get least of the two integers

       int least = num1;

       if(num1 > num2)

       {

           least = num2;

       }

       //Initialize gcd to 1

       int gcd = 1;

       //Calculate gcd using for loop

       for(int i=1;i<=least;i++)

       {

           if(num1%i == 0 && num2%i == 0)

           {

               gcd = i;

           }

       }

       if(gcd == 1)

       {

           System.out.print("GCD is 1");

       }

       else

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           System.out.print("GCD is "+gcd);

       }

   }

}

Explanation:

To calculate the GCD, the program uses a for loop that iterates from 1 to the smaller number of the user input.

Within this iteration, the program checks for a common divisor of the two user inputs by the iterating element

The GCD is then displayed afterwards;

However, if the GCD is 1; the program prints the message "GCD is 1"

<em>Line by Line Explanation</em>

This line declares two integer numbers

       int num1, num2;

This line allows user the program to accept user defined inputs        

Scanner input = new Scanner(System.in);

The next two line allows gets inputs from the user

<em>        num1 = input.nextInt();</em>

<em>        num2 = input.nextInt();</em>

<em />

To calculate the GCD, the smaller of the two numbers is needed. The smaller number is derived using the following if statement

<em>        int least = num1;</em>

<em>        if(num1 > num2)</em>

<em>        {</em>

<em>            least = num2;</em>

<em>        }</em>

The next line initializes GCD to 1

       int gcd = 1;

The GCD is calculated using the following for loop

The GCD is the highest number that can divide both numbers

<em>        for(int i=1;i<=least;i++)</em>

<em>        {</em>

<em>            if(num1%i == 0 && num2%i == 0)</em>

<em>            {</em>

<em>                gcd = i;</em>

<em>            }</em>

<em>        }</em>

The following is printed if the calculated GCD is 1

       if(gcd == 1)

       {

           System.out.print("GCD is 1");

       }

Otherwise, the following is printed

       else

       {

           System.out.print("GCD is "+gcd);

       }

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