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Bingel [31]
4 years ago
5

Which is most likely to cause confusion, hinder thinking, and prevent quick access to resources in a study environment? phones c

lutter noise laptops
phones
clutter
noise
laptops
Computers and Technology
2 answers:
Lerok [7]4 years ago
6 0

Answer:

clutter

Explanation:

edge 2020

OverLord2011 [107]4 years ago
3 0
Clutter will cause the most problems when you are trying to study because <span>If you’re unable to get through the material clogging up your </span>neural<span> networks, so the theory goes, you’ll be slower and less efficient in processing information. As a result, you’ll be incapacitated when it comes to short-term memory tasks, and even in longer-range mental exercises when you have to come up with information you should know, such as names of people, that you can no longer find within your disorganized repository of knowledge.

Hope this helps, 

kwrob</span>
You might be interested in
ABC Resort and Hotel has approached you to write a program to keep track of the number of rooms needed for an event. Customers c
nexus9112 [7]

Answer:

Check the explanation

Explanation:

/ Pseudocode for tracking the reservation of rooms for an event

Declaration

 

  string roomInput;

  string roomNames[4];

  number roomPrice[4];

  number roomCount[4];

  number i;

  boolean roomFound;

  number totalRevenue, avgRevenue;

  number totalRoomsNeeded;

Start

 

  // initialize the room names, and price for each room

  // array index starts from 0 and goes to n-1 where n is the total number of elements in the array

  roomNames[0] = "Single";

  roomNames[1] = "Single Deluxe";

  roomNames[2] = "Double";

  roomNames[3] = "Double Deluxe";

 

  roomPrice[0] = 79.95;

  roomPrice[1] = 99.95;

  roomPrice[2] = 149.95;

  roomPrice[3] = 179.95;

 

  // initialize each room count to 0 at the start

  for(i=0;i<4;i++)

  do

      roomCount[i] = 0;

  end for  

 

  // input the room type, user should type exit to indicate they are done

  Display "Enter room type ('exit' to quit ) : ";

  Input roomInput;

 

  // loop that continues till user types quit

  while(roomInput != "quit")

  do  

      roomFound = false;

      // loop to determine if user input is valid and increment the associated room count

      for(i=0;i<4;i++)

      do

          if(roomNames[i] == roomInput) then

              roomCount[i] = roomCount[i] + 1;

              roomFound = true;

          end if

      end for

     

      // if invalid room type, display error

      if(roomFound == false) then

          Display "Invalid input for Room type. Room type can be Single or Single Deluxe or Double or Double Deluxe ";

      end if  

     

      Display "Enter room type ('exit' to quit ) : ";

      Input roomInput;

  end while

 

  // set totalRevenue and totalRoomsNeeded to 0

  totalRevenue = 0;

  totalRoomsNeeded = 0;

  Display("Room Type Price($) Rooms Needed");

  // loop to display each room type details and calculate the totalRevenue and totalRoomsNeeded

  for(i=0;i<4;i++)

  do

      Display(roomNames[i],roomPrice[i],roomCount[i])

      totalRevenue = totalRevenue + (roomPrice[i]*roomCount[i]);

      totalRoomsNeeded = totalRoomsNeeded + roomCount[i];

  end for  

 

  // calculate average revenue

  if(totalRoomsNeeded > 0) then

      avgRevenue = totalRevenue/totalRoomsNeeded;

  else

      avgRevenue = 0;

  end if

 

  // display the total revenue and average revenue

  Display("Total revenue from all rooms : $",totalRevenue);

  Display("Average revenue from a room : $",avgRevenue);

 

End  

//end of pseudocode

5 0
3 years ago
This is an example of what type of formula?
slamgirl [31]

Answer:

Average

Explanation:

The term 'average' refers to the 'middle' or 'central' point. When used in mathematics, the term refers to a number that is a typical representation of a group of numbers (or data set). Averages can be calculated in different ways - this page covers the mean, median and mode.

3 0
2 years ago
Context-based signatures match a pattern of activity based on the other activity around it, such as a port scan. true and false
valina [46]

Answer:

The given statement is "True".

Explanation:

  • Context-based signatures become wired networks on either the incoming packet's information. Documentation included within the IP headers has been used to stimulate a certificate or stamp based on the scenario.
  • The whole category of signatures examines congestion and how much it appears to fit through the other pedestrians which mostly surrounds it.

So that the above is the true answer.

7 0
3 years ago
Python
andreyandreev [35.5K]

Answer:

<h2>1)   </h2>

h = 19  # h is already assigned a positive integer value 19

i = 1  # used to calculate perfect square

q = 0   # stores the sum of the perfect squares

while q < h:  

# this loop executes until value of number of perfect squares is less than h

   q = q + (i*i)  # to calculate the sum of perfect squares

   i = i + 1  # increments i by 1 at every iteration

print(q) # displays the sum of perfect squares

Output:

30

Explanation:

Here we see that the sum of the perfect square is printed in the output i.e. 30. If we want to assign value 4 to q then we should alter the code as  following:  

h = 19

i = 1

sum_of_ps = 0

q=0

while sum_of_ps < h:

   sum_of_ps = sum_of_ps + (i*i)

   q = q + 1

   i = i + 1  

print(q)  

If you want to take input from the user and also display the perfect squares in output you can use the following code:

h = int(input('Enter the value of h: ')) #takes value of h from user

i = 1

sum_of_ps = 0

q=0

while sum_of_ps < h:

   sum_of_ps = sum_of_ps + (i*i)

   print(i*i) #displays the perfect squares of h

   q = q + 1

   i = i + 1    

print(sum_of_ps)   #displays sum of perfect squares

print(q) #displays number of perfect squares whose value is less than h

Output:

1

4

9

16

30

4

<h2>2)</h2>

# k and m are already assigned positive integers 10 and 40

k = 10  

m = 40  

i = 1  # i is initialized to 1

q = 0  # q stores the number of perfect squares between k and m

while i*i < m:  # loop computes perfect square of numbers between k and m

   if i*i > k:          

       q = q + 1  # counts the number of perfect squares

   i = i + 1  #increments the value of i at each iteration

print (q) # prints the no of perfect squares between k and m

If you want to display the perfect squares too use , add print(i*i) statement after if statement  if i*i > k:        

Output:

3

<h2>3)</h2>

def Fibonacci(n):  # method Fibonacci which has an integer parameter n

   if n <= 1:  # if the value of n is less than or equals to 1

       result = n  # stores the value of n into result

   elif n > 1:  # else if the value of n is greater than 1

       result = Fibonacci(n-1) + Fibonacci(n-2)  

# calls Fibonacci method recursively to associate nth value of Fibonacci #sequence with variable result

   return result     #returns the final value stored in result variable

print(Fibonacci(8))

#calls Fibonacci function and passes value 8 to it

Output:

21

8 0
3 years ago
Write a program that estimate the temperature in a freezer(in oC) given the elapsed time (hours) since a power failure.Assume th
kaheart [24]

Answer:

#include <bits/stdc++.h>

using namespace std;

int main() {

  double time_h,temp_c;//declaring two variables for time and temperature of type double.

  cout<<"Enter the time"<<endl;

  cin>>time_h;//taking input of the time...

  temp_c=((4*2*time_h)/(time_h+2)-20);//calculating the temperature...

  cout<<temp_c<<endl;//printing the temperature..

return 0;

}

Explanation:

I have taken 2 variables of type double.

I am taking input of time from the user.

Then after that calculating the time according to the equation.

Then printing the output.

4 0
3 years ago
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