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3 years ago

HELP Explain the Triangle Inequality Theorem as it relates to angles.

Mathematics

1 answer:

zaharov [31]3 years ago

7 0

Answer:

If two sides of a triangle are unequal, then the measures of the angles opposite these sides are unequal, and the greater angle is opposite the greater side.

have a great day and easter

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Which expression is equivalent to 4x-9+6y+17x

Alexxx [7]

21x-9+6y

combining terms: 4x+17x=21x

6 0

3 years ago

Read 2 more answers

In a competition between players X and Y, the first player to win three games in a row or a total of four games wins. How many w

OLEGan [10]

Answer:

The competition can be played in 7 different ways

Step-by-step explanation:

First game : X

Second game : Y

Third game : Y

After that either X or Y can win

<h3>¹Case - 1: Y wins the fourth game:</h3>

The competition ends with Y winning as he/she won 3 games in a row

<h3>Case - 2: X wins the fourth game:</h3>

more games are required to decide the winner

<h3>Sub-case - a: X wins the fifth game:</h3>

more games are required to decide the winner

<h3>²Sub-sub-case - i: X wins the sixth game:</h3>

The competition ends with X winning as he/she won 3 games in a row

<h3>³⁻⁴Sub-sub-case - ii: Y wins the sixth game:</h3>

The competition ends after the seventh game. Whoever wins seventh game wins the competition as he/she would've won 4 games in total by then.

<h3>Sub-case - b: Y wins the fifth game:</h3>

more games are required to decide the winner

<h3>⁵Sub-sub-case - i: Y wins the sixth game:</h3>

The competition ends with Y winning as he/she won 4 games in total

<h3>⁶⁻⁷Sub-sub-case - ii: X wins the sixth game:</h3>

The competition ends after the seventh game. Whoever wins seventh game wins the competition as he/she would've won 4 games in total by then.

∴<u>The competition can be played in 7 different ways</u>

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4 years ago

Can someone please help me with this :( asap

Rama09 [41]

こんにちは

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3 years ago

Which shows the expressions in the order they would appear on a number line from least to greatest?

Illusion [34]

<span>c.)11 over 9, square root of 5, square root of 11, square root of 20, 2 to the power of 3

In order to compare, try to bring all of them into one similar form, like decimal.
Then, 11/9 = 1.22
Then, we can compare numbers under root, as 5 would be smaller than 11 which in turn is smaller than the 20, then 2^3 is 8, largest in series.

Hope this helps!</span>

6 0

3 years ago

Read 2 more answers

Evaluate the following

IRINA_888 [86]

(a) $[\frac{9}{2.6} - \frac{2.5^{2} }{2.5} ]^{2}$

Answer:

$[\frac{9}{2.6} - \frac{2.5^{2} }{2.5} ]^{2}$

= $[\frac{9}{2.6} - \frac{2.5*2.5 }{2.5} ]^{2}$

= $[\frac{9}{2.6} - \frac{2.5}{1} ]^{2}$

*canceling 2.5 in numerator and denominator*

$= [\frac{9-(2.5)(2.6)}{2.6} ]^2\\*Using L.C.M of 2.6 and 1 which comes out to be '2.6'= [\frac{9-(6.5)}{2.6} ]^2\\= [\frac{2.5}{2.6} ]^2\\*multiplying and dividing by '10'= [\frac{2.5*10}{2.6*10} ]^2\\= [\frac{25}{26} ]^2\\= \frac{25^2}{26^2}\\= \frac{625}{676}\\= 0.925$

Properties used:

Cancellation property of fractions

Least Common Multiplier(LCM)

The least or smallest common multiple of any two or more given natural numbers are termed as LCM. For example, LCM of 10, 15, and 20 is 60.

(b) $[[\frac{3x^{a}y^{b}} {-3x^{a} y^{b} } ]^{3} ] ^{2}$

Answer:

$[[\frac{3x^{a}y^{b}} {-3x^{a} y^{b} } ]^{3}] ^{2}\\$

*using $[x^{a}]^b = x^{ab}$ *

$= [\frac{3x^{3a}y^{3b}} {-3x^{3a} y^{3b} }] ^{2}$

*Again, using $[x^{a}]^b = x^{ab}$ *

$= \frac{3x^{2*3a}y^{2*3b}} {-3x^{2*3a} y^{2*3b} } \\= (-1)\frac{3x^{6a}y^{6b}} {3x^{6a} y^{6b} }\\[\tex]*taking -1 common, denominator and numerator are equal*[tex]= -(1)\frac{1}{1}\\= -1$

Property used: 'Power of a power'

We can raise a power to a power

(x^2)4=(x⋅x)⋅(x⋅x)⋅(x⋅x)⋅(x⋅x)=x^8

This is called the power of a power property and says that to find a power of a power you just have to multiply the exponents.

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3 years ago