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Likurg_2 [28]
3 years ago
14

Which equation has solution x = -3?

Mathematics
1 answer:
dybincka [34]3 years ago
7 0
I don’t know the answer but I hope someone else does:)

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The measure (in inches) of the sides of triangle RIO are equivalent to three consecutive odd integers. The perimeter is 201 inch
mariarad [96]
Let 
x-------------> first odd integer
x+2---------> second odd integer
x+4---------> third odd integer

we know that
(x)+(x+2)+(x+4)=201--------> 3x+6=201--------> 3x=195-------> x=65

the three <span>sides of triangle RIO are 
</span>x=65 in
x+2-----> 65+2-----> 67 in
x+4----> 65+4------> 69 in

then
69²=4761----------> c²
(65²+67²)=8714--------> a²+b²
c² < (a²+b²)---------> the triangle RIO is not obtuse
Is acute angle triangle

<span>statements 
1) </span><span>The triangle is obtuse--------> is false
</span>Is acute angle triangle
<span>
2) </span><span>The triangle is scalene-----> is correct
The three sides measures are diferent 

3)</span><span>The smallest side measures 61 inches--------> is false
</span><span>The smallest side measures 65 in
</span><span>
4)</span><span>The largest side measures 69 inches-------> is correct
</span><span>
5) </span><span>If triangle RIO is dilated of 1/3, then the perimeter of the dilated triangle will be 3 units smaller
</span><span>If triangle RIO is dilated of 1/3, then news sides are
</span>65/3------> 21.67 in
67/3-------> 22.33 in
69/3------> 23 in

the new perimeter is=21.67+22.33+23------> 67 in
201-67=134 in
therefore
If triangle RIO is dilated of 1/3, then the perimeter of the dilated triangle will be 3 units smaller----------> is false

Because the perimeter of the dilated triangle will be 134 units smaller

6 0
3 years ago
Read 2 more answers
7 - (-11) = _ <br><br> Please help having trouble with answer
stepladder [879]
Use long addition to evaluate: the answer is 18
8 0
3 years ago
If 3x + 6 = 18, then x = ?
zaharov [31]

Answer:

X=4

Step-by-step explanation:

3x + 6 = 18 \\ 3x = 18 - 6 \\ 3x = 12 \\ x = 4

7 0
3 years ago
-4x+16=12 what is the answer
ale4655 [162]

Answer:

1

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Evaluate the integral. (remember to use absolute values where appropriate. Use c for the constant of integration.) 5 cot5(θ) sin
ozzi

I=5\int \frac{cos^{4}\theta }{sin\theta }\times cos\theta d\theta \\\\I=5\int \left ( 1-sin^{2}\theta  \right )^{2}\times \frac{cos\theta }{sin\theta }d\theta \\put\ \sin\theta =t\\\\dt=cos\theta d\theta \\\\I=5\int\frac{t^{4}+1-2t^{2}}{t}dt\ \ \ \ \ \ \ \ \ \ \because (a-b)^2=a^2+b^2-2ab\\\\I=5\left ( \int t^{3}dt + \int \frac{1}{t} -2\int t \right )dt

by using the integration formula

we get,

\\I=5\left ( \frac{t^{4}}{4} +logt -t^{2}\right )\\\\I=\frac{5}{4}t^{4}+5\log t-5t^{2}+c

now put the value of t=\sin\theta in the above equation

we get,

\int 5\cot^5\theta \sin^4\theta d\theta=\frac{5}{4}sin^{4}\theta+5\log \sin\theta - 5sin^{2} \theta+c

hence proved

7 0
3 years ago
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