Answer:
a = 24
Step-by-step explanation:
Answer: (b)-175 ft
Step-by-step explanation:
In 
![\angle ACB=\angle ECD\quad [\text{vertically opposite angles}]\\\angle ABC=\angle CDE\quad [\text{Each angle is }90^{\circ}]\\\therefore \triangle ABC \sim\ \triangle CDE\quad [\text{by AA similarity criteria}]](https://tex.z-dn.net/?f=%5Cangle%20ACB%3D%5Cangle%20ECD%5Cquad%20%5B%5Ctext%7Bvertically%20opposite%20angles%7D%5D%5C%5C%5Cangle%20ABC%3D%5Cangle%20CDE%5Cquad%20%5B%5Ctext%7BEach%20angle%20is%20%7D90%5E%7B%5Ccirc%7D%5D%5C%5C%5Ctherefore%20%5Ctriangle%20ABC%20%5Csim%5C%20%5Ctriangle%20CDE%5Cquad%20%5B%5Ctext%7Bby%20AA%20similarity%20criteria%7D%5D)
(ii)for similar triangles, we can write
Answer:
23:22
Step-by-step explanation:
-6 and 4.5
So to do this you’ll make an equation x will represent the number so 4x^2+6x=108 so we want the equation to equal 0 so we can solve it to do that you have to subtract 108 from both sides so it ends up being 4x^2+6x-108=0 we want to isolate the x onto one side and division property allows us to divide both sides by 2 the reason it’s two is because 2 is the biggest divisible number that every number in the equation is divisible by so once you divide every number by two you get 2x^2+3x-54=0 now you have to factor cause but since you only have 3x and nothing else to factor with you have to write 3x as a difference so you could do 2x^2+12x-9x-54=0 so you are complicating the problem so you can factor out 2x from the expression so 2x(x+6)- 9(x+6)=0 the 54 got factored because it’s divisible by 9 that 6 is in replace of the 54 cause if you solved it 9x6 is still 54 next factor out x+6 so (x+6) x (2x-9) =0 so one of the two have to equal 0 so right the equations separately x+6=0 minus 6 from both sides and you’ll get x to equal -6 and 2x-9=0 add 9 to both sides and you’ll get 2x=9 divide both sides by 9 and you’ll get x to equal 4.5 when you plug 4.5 and -6 for x the equation works out
Answer:
#3. a non-terminating and non-repeating
Step-by-step explanation:
6.55743... never ends and it never repeats either
