1 - For this one I am not too sure as I generally only work with values that require an unknown. This one is an unknown asking for the values to see the fraction equivalent to 3/4 however if I had to guess here it would probably be 9/12 as it asks what is equal to 3/4. 3 goes into 9 3 times and into 12 4 times so it equals 3/4. Note: 9/12 has a numerator less than the denom but so does 6/8 which is the lesser fraction and still equals 3/4.
2 - Well simply put.
3 - For this one we have to do a bit of work.
Basically just make an equation such as n for numerator and d for denominator.
d = 2n - 4
Now all we have to do is plug in.
2 * 3 - 4 = 2
<span>2 * 6 - 4 = 8 </span>
<span>2 * 9 - 4 = 14 </span>
<span>2 * 12 - 4 = 20
</span>So now we know our numerator or n equals 12.
The denominator or d equals 20 so we would get the fraction of....
Answer:
5000 AED is the typical max limit for most banks.
Step-by-step explanation:
5000 AED is the typical max limit for most banks. A few would allow you to withdraw up to 8000, if you use the ATM machines of the bank that issued the card. So, 3500 AED shouldn't be a problem.
Answer:
The variables in a study of a cause-and-effect relationship are called the independent and dependent variables. The independent variable is the cause. ... The dependent variable is the effect. Its value depends on changes in the independent variable.
Step-by-step explanation:
Answer:
Where is your question?
Step-by-step explanation:
Answer:
heterozygous (Aa) are 0.085 = or 8.54%
Step-by-step explanation:
The heterozygous individuals are carriers of the sickle cell trait. They have a genotype of Aa and are represented by the 2pq term
in the H-W equilibrium equations.
According to the question 0.2% of the population is affected with sickle cell anemia, thus q^2
= 0.2% = 0.002 in decimal. So, q =
sqr(q^2)
or sqr(0.002) =
0.04472
and p + q = 1, thus p = 1 – q = 1 – 0.04472 = 0.96
Thus, A allele has a frequency of 0.96 and the a allele has a frequency of 0.04472. Therefore, the
percentage of the population that is heterozygous (Aa) and are carriers is = 2pq = 2× 0.04472× 0.96 =0.085 = or 8.54%