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3 years ago

Twice the sum of a number and 7 is equal to three times the difference of the number and 8. Find the number.

Mathematics

1 answer:

amm18123 years ago

3 0

Answer:

the number is 10.

Step-by-step explanation:

2(x + 7) = 3(x - 8)

2x + 14 = 3x - 24

2x = 3x -10

x = 10

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If f(x) = 4x - 7, what's the value of f(2) ? * O -1 O 1 O 20 O 35

sp2606 [1]

Answer:

Step-by-step explanation:

f(x) = 4x - 7

What does f(x) mean? It means that whatever variable you have on the left which is (x), the same variable must be on the right.

So f(2) means that whatever variable is on the right, it must be replaced with 2 on the right. So .....

f(2) = 4(2) - 7

f(2) = 8 - 7

f(2) = 1

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2 years ago

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Vaselesa [24]

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3 years ago

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juin [17]

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2 years ago

Let f(x) = 7x − 13. Find f−1(x)

motikmotik

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3 years ago

Here are the endpoints of the segments BC, FG, and JK. B, −67

yulyashka [42]

$~~~~~~~~~~~~\textit{distance between 2 points} \\\\ B(\stackrel{x_1}{-6}~,~\stackrel{y_1}{7})\qquad C(\stackrel{x_2}{-4}~,~\stackrel{y_2}{4})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ BC=\sqrt{[-4 - (-6)]^2 + [4 - 7]^2}\implies BC=\sqrt{(-4+6)^2+(-3)^2} \\\\\\ BC=\sqrt{2^2+(-3)^2}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{distance between 2 points}$

$F(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-4})\qquad G(\stackrel{x_2}{1}~,~\stackrel{y_2}{-2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ FG=\sqrt{[1 - (-2)]^2 + [-2 - (-4)]^2}\implies FG=\sqrt{(1+2)^2+(-2+4)^2} \\\\\\ FG=\sqrt{9+4}\implies \boxed{FG=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ J(\stackrel{x_1}{4}~,~\stackrel{y_1}{2})\qquad K(\stackrel{x_2}{5}~,~\stackrel{y_2}{-2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}$

$JK=\sqrt{[5 - 4]^2 + [-2 - 2]^2}\implies JK=\sqrt{1^2+(-4)^2}\implies \boxed{JK=\sqrt{17}} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \overline{BC}\cong \overline{FG}~\hfill$

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1 year ago