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noname [10]
3 years ago
6

Pls help i need the answer

Mathematics
1 answer:
san4es73 [151]3 years ago
7 0

Answer:

(3,22.50)

(6, 33)

Rise/Run using two points

33-22.50/ 6-3

10.5/3

<u>Rate = 3.5</u>

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How many packages of noisemakers does Mia need to buy? How many packages of hats? Explain. Write your answer in the space below.
Sedaia [141]

Answer:

23

Step-by-step explanation:

Is what I would say

5 0
3 years ago
Given the quadriatic equation
vazorg [7]

Answer:

⇒  The given quadratic equation is x2−kx+9=0, comparing it with ax2+bx+c=0

∴  We get, a=1b=−k,c=9

⇒  It is given that roots are real and distinct.

∴  b2−4ac>0

⇒  (−k)2−4(1)(9)>0

⇒  k2−36>0

⇒  k2>36

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8 0
2 years ago
For the region bounded by y=2x​, the​ x-axis, and x=1​, determine which of the following is​ greater: the volume of the solid ge
telo118 [61]

Answer:

The correct answer B) The volumes are equal.

Step-by-step explanation:

The area of a disk of revolution at any x about the x- axis is πy² where y=2x. If we integrate this area on the given range of values of x from x=0 to x=1 , we will get the volume of revolution about the x-axis, which here equals,

\int\limits^1_0 {(pi)y^{2} } \, dx

which when evaluated gives 4pi/3.

Now we have to calculate the volume of revolution about the y-axis. For that we have to first see by drawing the diagram that the area of the CD like disk centered about the y-axis for any y, as we rotate the triangular area given in the question would be pi - pi*x². if we integrate this area over the range of value of y that is from y=0 to y=2 , we will obtain the volume of revolution about the y-axis, which is given by,

\int\limits^2_0 {pi - pix^{2} } \, dy = \int\limits^2_0 {1 - y^{2}/4 } \, dy

If we just evaluate the integral as usual we will get 4pi/3 again(In the second step i have just replaced x with y/2 as given by the equation of the line), which is the same answer we got for the volume of revolution about the x-axis. Which means that the answer B) is correct.

7 0
3 years ago
Among 35 students in a class, 20 of them earned A's on the midterm exam, 13 earned A's on the nal exam, and 12 did not earn A's
enyata [817]

Answer:

The correct answer is "\frac{2}{7}".

Step-by-step explanation:

According to the question,

Number of students,

= 35

A ! mid term A,

n(A) = 20

B : final A,

n(B) = 13

Didn't start,

n(A^c \cap B^c) = 12

Now,

⇒ n(A \cup B)=35-12

                   =23

then,

⇒ n(A \cup B)=20+13-23

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hence,

The probability will be:

⇒ P(A \cap B)=\frac{10}{35}

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3 years ago
What is the area of this triangle?
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