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2 years ago

Skylar drove 280 miles in 5 hours. If she continued at the same rate, how far would

Mathematics

1 answer:

erica [24]2 years ago

5 0

Answer:

1,120

Step-by-step explanation:

If you divide 280 and 5 you get 56. Then you multiply 56 and 20 and you get 1,120

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I need help!!! ill give brain-list!!!

In-s [12.5K]

Answer:

8 hours worked, 64 dollars

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2 years ago

The moon is about 240,000 miles from earth what is this distance written as a whole number multiplied by a power of ten

kiruha [24]

The answer is 24 times 10^4

5 0

2 years ago

Consider the expression: (x + y + 3) × (y + 1).

Vladimir79 [104]

Answer:

1 and 2) After multiplying (x+y+3)(y+1) we have

xy+x+y^2+4y+3

Which is an equivalent expression after applying the distributive property.

As we can see we have an one of the variables squared, so we obtain an Parabolic Cillinder

4 0

3 years ago

Helppp Plsss Asap!! Thanks!!

LenKa [72]

the answer is 12 because if you look at the position of the y axis when x equals 2 then look at the y value when x equals 4 you will get the 2 numbers 4 and 16 now subtract 16 by 4 and you get 12.

8 0

2 years ago

Read 2 more answers

Each of 12 refrigerators of a certain type has been returned to a distributor because of an audible, highpitched, oscillating no

garik1379 [7]

Answer:

0.121

Step-by-step explanation:

From the given information:

Let X be a hypergeometric random variable. i.e X $\sim$ h (x;:6,7,12)

To determine the mean and the standard deviation of X of a hypergeometric random variable; we have:

$\mu_x = E(X)$

$\mu_x = 6 \times \dfrac{7}{12}$

$\mu_x =1 \times \dfrac{7}{2}$

$\mu_x =3.5$

The standard deviation is :

$\sigma _x = \sqrt{(\dfrac{12-6}{12-1}) \times 6 \times (\dfrac{7}{12})\times (1-\dfrac{7}{12})}$

$\sigma _x = \sqrt{(\dfrac{6}{11}) \times 6 \times (\dfrac{7}{12})\times (\dfrac{5}{12})}$

$\sigma _x = \sqrt{\dfrac{35}{44}}$

$\sigma _x = 0.892$

However, the inequality for the event showcasing how X exceeds its mean value by more than 1 standard deviation is :

$X \geq \mu_x +\sigma_x$

$X \geq 3.5 +0.892$

$X \geq 4.392$

$X \geq 5$

∴

$P(X \geq \mu_x + \sigma_x ) = P(X \geq 5)$

$P(X \geq \mu_x + \sigma_x ) = 0.121$

7 0

3 years ago