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Y_Kistochka [10]

3 years ago

12

HELP PLS YALL HDHDGDUSHSHXHHXXHHXHXBXBXXHDBBDBDBDBDD

1 answer:

Vedmedyk [2.9K]3 years ago

5 0

Answer:

with what?

Step-by-step explanation:

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find 2 consecutive integers such that three times the square of the first is equal to seven more than five times the second

melamori03 [73]

Answer:

Step-by-step explanation:

We are looking for two numbers, $N$ and $N + 1$ . From the problem statement, we can setup the following equation:

$3N^{2} = 5(N + 1) + 7$

$3N^{2} = 5N + 5 + 7$

$3N^{2} - 5N - 12 = 0$

$(3N + 4)(N - 3)$

$N = \frac{-4}{3}, 3$

Because 3 is the only integer solution, the answer is 3 and 4.

5 0

3 years ago

A winter sport passed at Wood Middle school costs $15. A stydent without a pass must pay $1.75 for each event. How many events w

azamat

Nine events for a pass to be a better deal

4 0

3 years ago

Choose the solution(s) of the following system of equations x2 + y2 = 6 x2 – y = 6

ElenaW [278]

<h2>Answer</h2>

$x=\sqrt{6}, y=0\\ x=-\sqrt{6} , y=0\\x=\sqrt{5} , y=-1\\x=-\sqrt{5} , y=-1$

Or as ordered pairs: $(\sqrt{6} ,0),(-\sqrt{6} ,0),(\sqrt{5} ,-1),(-\sqrt{5} ,-1)$

<h2>Explanation</h2>

Lets solve our system of equations step by step

$x^2+y^2=6$ equation (1)

$x^2-y=6$ equation (2)

1. Solve for $x^2$ in equation (2)

$x^2-y=6$

$x^2=6+y$ equation (3)

2. Replace equation (3) in equation (1) and solve for $y$

$x^2+y^2=6$

$6+y+y^2=6$

$y^2+y=0$

$y(y+1)=0$

$y=0$ or $y=-1$

3. Replace the values of $y$ in equation (3) and solve for $x$

- For $y=0$

$x^2=6+y$

$x^2=6$

$x=\sqrt{6}$ or $x=-\sqrt{6}$

- For $y=-1$

$x^2=6+y$

$x^2=6-1$

$x^2=5$

$x=\sqrt{5}$ or $x=-\sqrt{5}$

So, the solutions of our system of equation are:

$x=\sqrt{6}, y=0\\ x=-\sqrt{6} , y=0\\x=\sqrt{5} , y=-1\\x=-\sqrt{5} , y=-1$

6 0

3 years ago

Read 2 more answers

If x = 4 units, y = 5 units, and h = 4 units, find the area of the rhombus shown above using decomposition.

QveST [7]

A. 36 square units
(Please tell me if I’m right in the comments)
Have a wonderful day!

4 0

2 years ago

Find the area of the shaded region.<br> help pls

umka2103 [35]

Answer:

1. 50 m

2. 80 cm

Step-by-step explanation:

1. There are 2 triangles, subtract the area of 1 of them from the other.

The triangle that needs to be subtracted: b = 20 m, h = 10 m

A = 1/2b * h = 1/2(20) * 10 = 10*10 = 100 m

The big triangle, the one that needs to be subtracted plus the one you need to find the area of: b = 20 cm, h = 15 cm, 1/2(20) * 15 = 10 * 15 = 150

150 - 100 = 50 c

2. Divide it into 3 parts:

1- 3*4 = 12

2. 7*(4 + 4) = 7*8 = 56

3. [(4 + 4) * (13 - 7 - 3)]/2 = (8*3)/2 = 24/2 = 12

12 + 56 + 12 = 80 cm

7 0

3 years ago