The square root of 11 since it can’t be solved repeating the same every time like the others! Hope this helps ☺️
<u>Answer:</u>
- The first four terms are <u>4</u><u>,</u><u>8</u><u>,</u><u>1</u><u>2</u><u>,</u><u>1</u><u>6</u>
<u>Step-by-Step </u><u>Explanation</u><u>:</u>
The given relation between the nth term and it's previous term is given by:

GiveN:
Now finding the other three terms of the AP with the given relation.

Putting a1 = 4,

Now, Third term:

Putting a2 = 8,

Now, Fourth term:

Putting a3 = 12,

Hence, The first four terms of the AP is 4, 8, 12 & 16.
A = 5¹⁴⁹
B = 11⁹⁹
Case 1: A>B
Result: True
Case 2: A=B
Result: False
Case 3: AResult: False
Step-by-step explanation:
Aight, so the same intercept

m=½

soooo

Answer:
C) |–60 + 11| = |–49| = –49 units
Step-by-step explanation: