Using the Pythagorean theorem to solve this, d=26, here's how.
a^2+b^2=c^2
plug in the numbers you already have
10^2+24^2=d^2
100+578=676
676=d^2
take the square root of that
√676=26
d=26
Answer:
Area of sector bounded by angle = 100.37 ft² (Approx.)
Step-by-step explanation:
Given:
Radius of a circle = 12 feet
Arc angle θ = 80°
Find:
Area of sector bounded by angle
Computation:
Area of sector bounded by angle = [θ/360][πr²]
Area of sector bounded by angle = [80/360][(3.14)(12)²]
Area of sector bounded by angle =[0.22][(3.14)(144)]
Area of sector bounded by angle = [0.22][452.16]
Area of sector bounded by angle = 100.37 ft² (Approx.)
Let width and length be x and y respectively.
Perimeter (32in) =2x+2y=> 16=x+y => y=16-x
Area, A = xy = x(16-x) = 16x-x^2
The function to maximize is area: A=16 x-x^2
For maximum area, the first derivative of A =0 => A'=16-2x =0
Solving for x: 16-2x=0 =>2x=16 => x=8 in
And therefore, y=16-8 = 8 in
Answer:
1 2/3 hope this helps and have a wonderful day
