Answer:
12 3/4 same slope fro both
13 DE = 5, CB = 10
14 see below
Step-by-step explanation:
12. the slopes are the same
D(0, 3) E(4, 6) slope is (change in y)/(change in x)
change in y = 3 to 6 is a change of +3
Change in x = 0 to 4 is a change of +4
slope is 3/4
13 To fine lengths you can distance formula or Pythagorean theorem (spoiler: they are related to each other)
DE² = 3² + 4²
DE² = 9 + 12
DE² = 25
√DE² = √25 = 5
DE = 5
and
CB² = 6² + 8²
CB² = 36 + 64
CB² = 100
√CB² = √100 = 10
CB = 10
14. since the slopes are the same are DE is 1/2 or CB its is the mid segment. because (taken from mathopenref.com/trianglemidsegment.html)
The midsegment is always parallel to the third side of the triangle. In the figure above, drag any point around and convince yourself that this is always true.
The midsegment is always half the length of the third side. In the figure above, drag point A around. Notice the midsegment length never changes because the side BC never changes.
A triangle has three possible midsegments, depending on which pair of sides is initially joined.
You cannot assume the angles add to 90, but you know since BD is an angle bisector that ABD is equal to DBC, or x-5=2x-6
x=1. this is the correct solution to the equation but gives negative angles when plugged in which isn't possible. there must be something wrong work the question
525 feet above the ground
Answer: 45
Step-by-step explanation:
300 * 0.15 = 45
1) We calculate the volume of a metal bar (without the hole).
volume=area of hexagon x length
area of hexagon=(3√3 Side²)/2=(3√3(60 cm)²) / 2=9353.07 cm²
9353.07 cm²=9353.07 cm²(1 m² / 10000 cm²)=0.935 m²
Volume=(0.935 m²)(2 m)=1.871 m³
2) we calculate the volume of the parallelepiped
Volume of a parallelepiped= area of the section x length
area of the section=side²=(40 cm)²=1600 cm²
1600 cm²=(1600 cm²)(1 m² / 10000 cm²=0.16 m²
Volume of a parallelepiped=(0.16 m²)(2 m)=0.32 m³
3) we calculate the volume of a metal hollow bar:
volume of a metal hollow bar=volume of a metal bar - volume of a parallelepiped
Volume of a metal hollow bar=1.871 m³ - 0.32 m³=1.551 m³
4) we calculate the mass of the metal bar
density=mass/ volume ⇒ mass=density *volume
Data:
density=8.10³ kg/m³
volume=1.551 m³
mass=(8x10³ Kg/m³ )12. * (1.551 m³)=12.408x10³ Kg
answer: The mas of the metal bar is 12.408x10³ kg or 12408 kg
