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Rom4ik [11]
3 years ago
9

Zayed is helping his classmates get ready for their math test by making them identical packages of pencils and calculators.

Mathematics
1 answer:
meriva3 years ago
4 0

Answer:

9

Step-by-step explanation:

bc 9x8=72 and 9 is the greatest number so the answer is 9

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Patrick climbed 4/5 of the way up the trunk of a tree. Jacob climbed 80/100 of the way up the same tree. To accomplish the same
Ainat [17]

Answer:

Standard Description: Explain why a fraction a/b is equivalent to a fraction (n × a)/(n × b) by using visual fraction models, with attention to how the number and size of the parts differ even though the two fractions themselves are the same size. Use this principle to recognize and generate equivalent fractions. (Grade 4 expectations in this domain are limited to fractions with denominators 2, 3, 4, 5, 6, 8, 10, 12, and 100.)

Step-by-step explanation:

the explanation and answer is there in above

6 0
3 years ago
Solve using substitution: y + 2x = -1 and y - 3X = 16
marusya05 [52]

Answer:

Alright i'm just going to assume your doing both of them one at a time.


y + 2x = - 1: So Alright Graph using the slope and y-intercept

Slope: - 2

Y-intercept: - 1

And the other

- 3x = 16: same as well So the Answer to this is Except solve for x by simplifying both sides of the equation, then isolating the variable

Exact form: x = - 16/3

Decimal form: x = - 5.3 Well Hope this helps :)


Step-by-step explanation:


8 0
4 years ago
The quotient of a number m and 3.2 is 15
vaieri [72.5K]
M/3.2*3.2=15*3.2
M=48
I think
7 0
3 years ago
Read 2 more answers
What is 15/16 minus 12/16
Ksju [112]
15/16 - 12/16 = 3/16
6 0
3 years ago
One positive integer is 7 less than twice another. The sum of their squares is 346. Find the integers. should be 2 answers
vovikov84 [41]

Answer:

the two positive integers are x= 15, and y = 11

Step-by-step explanation:

Let the first integer be x

Let the second integer be y

from the problem we can decode the following equations

x=2y-7 ---------------------------- equation 1

x^{2} + y^{2}= 346 -------------------------equation 2

substituting the value of x into equation 2, we have

(2y-7)^{2} + y^{2}= 346 --------------equation 3

expanding, we have

4y^{2}-28y+49+y^{2}=346

5y^{2}-28y-297 = 0

from this, y = 11 or y = -5.4

since our answer is a positive integer, we will have to pick the first value of y which is y = 11

substituting the value of y into equation 1, we have

x= 2(11)-7=15

hence x = 15

Therefore, we have x= 15, and y = 11

these are the two positive integers

7 0
3 years ago
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