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4 years ago

Where in the atom are the electrons that are involved in chemical bonding located?

Chemistry

2 answers:

shepuryov [24]4 years ago

6 0

They are located outside of the cell.

riadik2000 [5.3K]4 years ago

3 0

It is located in the nucleus

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A certain element has a melting point over 700 ∘c and a density less than 2.00 g/cm3. give one possible identity for this elemen

Hunter-Best [27]

A melting point of over 700 C and a density of less than 2 g/cm3 can be observed for many group 2 elements. In this group, the density increases on moving down the group, whereas the melting point increases upto calcium and then starts decreasing.

Calcium, symbol Ca is the element with melting point around 840 C and density of 1.55 g/cm3 which is closest to the specified data range .

3 0

4 years ago

Is the Sun a star? Explain.

lesya692 [45]

Answer:

sun is a star because it has it own light. it don't need to reflect through others light

7 0

3 years ago

Can someone balance these equations?

wolverine [178]

This is mind numbing, but I got you.

3NaOH + 1FeCl3 = 1Fe(OH)3 + 3NaCl

3Mg + 2H3(PO)4 = 1Mg(PO4)2 + 3H2

3 0

3 years ago

How many moles and numbers of ions of each type are present in the following aqueous solution? 63.1 mL of 1.85 M magnesium chlor

Alexxandr [17]

Answer:

We have 0.117 moles Mg^2+ and 0.234 moles Cl-

The number of Mg^2+ ions = 7.04 *10^22 ions

The number of Cl- ions = 1.4*10^23 ions

Explanation:

Step 1: Data given

Volume of magnesium chloride = 63.1 mL

Concentration of solution = 1.85 M

Step 2: Calculate moles MgCl2

Moles MgCl2 = concentration * volume

Moles MgCl2 = 1.85 M * 0.0631 L

Moles MgCl2 = 0.117 moles

Step 3: Calculate moles of ions

MgCl2 → Mg^2+ + 2Cl-

For 1 mol MgCl2 we have 1 mol Mg^2+ and 2 moles Cl-

For 0.117 moles MgCl2 we have 0.117 moles Mg^2+ and 2*0.117 = 0.234 moles Cl-

The number of Mg^2+ ions = 0.117 * 6.022 *10^23 = 7.04 *10^22 ions

The number of Cl- ions = 1.4*10^23 ions

4 0

4 years ago

Perform the following conversions:

jek_recluse [69]

Answer :

The conversion used for the temperature from Fahrenheit to degree Celsius is:

$^oC=\frac{5}{9}\times (^oF-32)$

The conversion used for the temperature from degree Celsius to Kelvin is:

$K=^oC+273$

(a) $1.06^oF$

$^oC=\frac{5}{9}\times (^oF-32)$

$^oC=\frac{5}{9}\times (1.06^oF-32)$

$^oC=-17.188$

The temperature in degree Celsius is, $-17.188^oC$

$K=^oC+273$

$K=-17.188+273$

$K=255.812$

The temperature in Kelvin is, 255.812 K

(b) $3410^oC$

$^oC=\frac{5}{9}\times (^oF-32)$

$3410^oC=\frac{5}{9}\times (^oF-32)$

$^oF=6106$

The temperature in degree Fahrenheit is, $6106^oF$

$K=^oC+273$

$K=3410+273$

$K=3683$

The temperature in Kelvin is, 3683 K

(c) $6.1\times 10^3K$

$K=^oC+273$

$6.1\times 10^3K=^oC+273$

$^oC=5827$

The temperature in degree Celsius is, $5827^oC$

$^oC=\frac{5}{9}\times (^oF-32)$

$5827^oC=\frac{5}{9}\times (^oF-32)$

$^oF=10456.6$

The temperature in degree Fahrenheit is, $10456.6^oF$

8 0

3 years ago