It would be useful to memorize that sentence. Once you know that, you can figure out whatever else happens at the anode, the cathode, in the solution, and in the external circuit
Answer:
Answer choice B
Explanation:
Since you do not know the volume of the liquid in each beaker, the one in the smaller beaker could have more substance and therefore more thermal energy. If they had the same amount of substance, then the more voluminous one would radiate faster. However, since you do not know this, there is no way to tell. PM me if you have more questions. Hope this helps!
Answer:
B) -1.00 M/min
Explanation:
Based on the reaction:
2 SO2(g) + O2(g) → 2SO3(g)
<em>2 moles of SO2 are consumed per mole of O2 producing 2 moles SO3</em>
<em />
In the problem, the sulfur dioxide has a rate of change of -2.00M/min. As the moles of oxygen that reacted are half the moles of SO2, its rate of change is halved, that is:
<h3>B) -1.00 M/min
</h3>
C. CH3OH
hope this helped! :))
