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s344n2d4d5 [400]

2 years ago

15

LIMITED TIME PLS HELP: Four, two-person tennis teams played tennis matches. Ivan collected the number of points won by both play

ers on each team and arranged the information into matrices as shown below
Consider the total number of points played by each tennis team. How many teams won 60 points or less?

0
1
2
3

2 answers:

Marina86 [1]2 years ago

8 0

For this, you just need to add up the team points together. Also remember that the problem says "60 pts or less", not "less than 60 pts". This means teams with 60 pts will count for the question.

Team 1: $38+22=60$

Team 2: $42+18=60$

Team 3: $21+42=63$

Team 4: $25+40=65$

From the math above, we can conclude that 2 teams had won 60 or less.

Alexeev081 [22]2 years ago

6 0

Answer:

<h2>Team 1 and Team 2.</h2>

Step-by-step explanation:

To know how many teams won 60 points or less, we just need to sum all points per team and see which one is restricted to 60 points or less.

<h3>Team 1</h3>

38 + 22 = 60

<h3>Team 2</h3>

42 + 18 = 60

<h3>Team 3</h3>

21 + 42 = 63

<h3>Team 4</h3>

25 + 40 = 65

According to the given information, only two teams won 60 points, which are Team 1 and Team 2.

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Convert,the complex number into polar form: 4+4i

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Z = a + bi
z = 4 + 4i

r² = a² + b²
r² = (4)² + (4)²
r² = 16 + 16
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r = 4(1.414)
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$cos\theta = \frac{4}{4\sqrt{2}} * \frac{\sqrt{2}}{\sqrt{2}}$
$cos\theta = \frac{4\sqrt{2}}{4\sqrt{4}}$
$cos\theta = \frac{4\sqrt{2}}{4(2)}$
$cos\theta = \frac{4\sqrt{2}}{8}$
$cos\theta = \frac{\sqrt{2}}{2}$
$2(cos\theta) = 2(\frac{\sqrt{2}}{2})$
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$sin\theta = \frac{b}{r}$
$sin\theta = \frac{4}{4\sqrt{2}}$
$sin\theta = \frac{4}{4\sqrt{2}} * \frac{\sqrt{2}}{\sqrt{2}}$
$sin\theta = \frac{4\sqrt{2}}{4\sqrt{4}}$
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$2sin\theta = 1.414$

z = a + bi
z = rcosθ + (rsinθ)i
z = r(cosθ + i sinθ)

z = 4 + 4i
z = 5.656cosθ + (5.656sinθ)i
z = 5.656(cosθ + i sinθ)
z = 5.656(cos45 + i sin45)

$\theta = tan^{-1}\frac{b}{a}$
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The polar form of 4 + 4i is approximately equal to 5.656(cos45 + i sin45).

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