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Hoochie [10]
3 years ago
8

Solve 3=5^(x+1) using change of base

Mathematics
1 answer:
lana66690 [7]3 years ago
4 0

\bf \textit{Logarithm Change of Base Rule} \\\\ \log_a b\implies \cfrac{\log_c b}{\log_c a}\qquad \qquad c= \begin{array}{llll} \textit{common base for }\\ \textit{numerator and}\\ denominator \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ 3=5^{x+1}\implies \log_7(3)=\log_7\left( 5^{x+1} \right)\implies \log_7(3)=(x+1)\log_7(5) \\\\\\ \cfrac{\log_7(3)}{\log_7(5)}=x+1\implies \log_5(3)=x+1\implies \log_5(3)-1=x\implies -0.3174 \approx x

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<h3>Given :-</h3>
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\\  \\

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\\  \\

<h3>Let :</h3>

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<h3>Solution:</h3>

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Equation formed:-

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Arrange the equation because x is always represented at left side.

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\leadsto \boxed {\pmb{\sf x = 18.3}}\star

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Step-by-step explanation:

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