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Setler [38]
3 years ago
15

A) Let f(x) = 4x + 2 and g(x) = 2x^2-4. Find the formula for the composition function gof

Mathematics
1 answer:
ollegr [7]3 years ago
5 0

Answer:

g o f = g(f(x)) = 32x^2 + 32x + 4

Step-by-step explanation:

Given

f(x) = 4x +2

g(x) =2x^2 - 4

Required:

Find g o f

This is calculated as:

gof = g(f(x))

g(x) =2x^2 - 4

So:

g(f(x)) = 2(4x+2)^2 - 4

g(f(x)) = 2(4x+2)(4x+2) - 4

g(f(x)) = 2[ 16x^2 + 16x + 4)] - 4

g(f(x)) = 32x^2 + 32x + 8 - 4

g(f(x)) = 32x^2 + 32x + 4

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A restaurant served Six slices of pie during lunch and lunch and 4 during dinner today how many slices of pie were served today
rewona [7]

Answer:

10 (?)

Step-by-step explanation:

6 during lunch + 4 during dinner would be 10. Not sure why you said lunch twice.

7 0
3 years ago
A book club has 200 members
nikklg [1K]
So these are decmials of the accutal total so

.32=32%
what makes this question easy is that there are 200 members so to convert the percents into accutall numbers so like .32=32%=64 people (since 200 is 2 times of 100)

A. fiction of 31-40 compared to 21-30
fiction 31-40=.38=38%=76 readers
fiction 21-30=.32=32%=64 readers
76-64=12
A is FALSE

B. so we want to know how many people are 31-40 and prefer fiction
so .38=38% and 38% of 200=76
B is FALSE

C 43 members are 21-30
so we look at the total row for the 21-30 people and see that .43 or 43% or 86 people are in the 21-30 age group
C is FALSE

D. 140 members prefer fiction
look at the total column for fiction and see that .70 like fiction .70=70%=140 people
D is TRUE

so A,B,C are FALSE
D is TRUE
7 0
3 years ago
Please help asap 23 pts
Colt1911 [192]

That would be point E since it is between 1 and 2 on the number line and is a little bit closer to 2. hope this helps

3 0
3 years ago
Read 2 more answers
How do you change 13/10 to a mixed number
MrRa [10]
13/10 so 10/10=1
13-10=3

1 3/10 is 13/10 as a mixed number

hope that helps!
8 0
2 years ago
Read 2 more answers
3{x}^{4}-15{x}^{2}+12=0
MA_775_DIABLO [31]

3x^4-15x^2+12=0\qquad|:3\\\\x^4-5x^2+4=0\\\\x^4-x^2-4x^2+4=0\\\\x^2(x^2-1)-4(x^2-1)=0\\\\(x^2-1)(x^2-4)+0\iff x^2-1=0\ \vee\ x^2-4=0\\\\x^2=1\ \vee\ x^2=4\\\\x=\pm\sqrt1\ \vee\ x=\pm\sqrt4\\\\\boxed{x=-1\ \vee\ x=1\ \vee\ x=-2\ \vee\ x=2}

6 0
2 years ago
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