I need help with this ASAP plz!!!!
1 answer:
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The height of the rocket above the ground after seconds is given by the equation :
, where
is the initial velocity and
is the initial height.
Given that, and
So, the equation will become:
A) For finding the height of the rocket 3 seconds after the launch, we will <u>plug into the above equation</u>. So....
So, the height of the rocket 3 seconds after the launch is 1376 feet.
B) When the rocket at a height of 400 feet, then <u>we will plug </u>
Using quadratic formula, we will get......
So, after 0.7794...seconds and 30.4705...seconds the rocket is at a height of 400 feet above the ground.
C) The time duration that the rocket remains in the air means we need to find <u>the time taken by the rocket to reach the ground</u>. When it reaches the ground, then . So.....
Using <u>quadratic formula</u>, we will get.....
<em>(Negative value is ignored as time can't be in negative)</em>
So, the rocket will remain in the air for 31.2899... seconds.
Answer:
$ 297.87 interest
Step-by-step explanation:
Calculate the amount and the compound interest.
Amount = PNR Where P is Principal ; N is the no of Terms and R is the rate of interest
Amount of 1 st quarter = $ 9,855 x 6 % x = $147.83
Compound interest is $ 9,855 + 147.83= $ 10,002.83
Amount of 2 nd quarter , 10,002.83 x 6% x = $150.04
Compound Interest is 10,002.83 + 150.04 = $10,152.87 amount
10,152.87 - 9,855= $297.87 interest