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3 years ago

In a class of 6, there are 2 students who forgot their lunch.

Mathematics

1 answer:

lukranit [14]3 years ago

4 0

Answer:

1/8

Step-by-step explanation:

AB,AA,BB,BB,BB,BB,BB,BB,

*A IS THE students that forgot thier lunch

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Which ordered pair would form a proportional relationship with the point graphed below? On a coordinate plane, a line with negat

avanturin [10]

Answer:

Answer:

(5, 20)

Step-by-step explanation:

We can find the slope of the line

m = (y2-y1)/(x2-x1)

= (40-0)/(10-0)

= 40/10

Since the line goes through (0,0) the y intercept is 0

y = mx+b

y = 4x

Lets check the points by substituting into the equation

40, 10) 10 = 4*40 10 =160 no

(–5, –10) -10 = 4*-5 10 = -20 no

(5, 20) 20 = 4*5 20 = 20 yes

(–10, –20) -20 = 4*-10 -20 = -40 no

Step-by-step explanation:

Which ordered pair would form a proportional relationship with the point graphed below? On a coordinate plane, a line with negative slope goes through points (negative 20, 10), (0, 0), and (20, negative 10). (10, –20) (–30, 20) (–10, 5) (35, –20)

4 0

3 years ago

Read 2 more answers

Can somebody help me find the surface area of this

-Dominant- [34]

Answer:

G. 7600 $cm^{2}$

Step-by-step explanation:

Step 1: Deconstruct the shape

2 rectangles with dimension of 50 cm x 20 cm

2 rectangles with dimension of 40 cm x 20 cm

2 rectangles with dimension of 40 cm x 50 cm

Step 2: Find surface area of the shapes

2(50 x 20) = 2000 $cm^{2}$

2(40 x 20) = 1600 $cm^{2}$

2(40 x 50) = 4000 $cm^{2}$

Step 3: Add the surface areas together

2000 + 1600 + 4000 = 7600 $cm^{2}$

Therefore the surface area is 7600 $cm^{2}$ and the answer is G.

4 0

3 years ago

Write the equation of the line that passes through (−3,1) and (2,−1) in slope-intercept form

Alex787 [66]

Answer:

$y=-\frac{2}{5}x-\frac{1}{5}$

Step-by-step explanation:

The equation of a line is y = mx + b

Where:

m is the slope

b is the y-intercept

First, let's find what m is, the slope of the line.

Let's call the first point you gave, (-3,1), point #1, so the x and y numbers given will be called x1 and y1.

Also, let's call the second point you gave, (2,-1), point #2, so the x and y numbers here will be called x2 and y2.

Now, just plug the numbers into the formula for m above, like this:

$m = -\frac{2}{5}$

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

$y=-\frac{2}{5}x + b$

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

(-3,1). When x of the line is -3, y of the line must be 1.
(2,-1). When x of the line is 2, y of the line must be -1.

Now, look at our line's equation so far: $y=-\frac{2}{5}x + b$ . $b$ is what we want, the - $-\frac{2}{5}$ is already set and x and y are just two 'free variables' sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (-3,1) and (2,-1).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!

You can use either (x,y) point you want. The answer will be the same:

(-3,1). y = mx + b or $1=-\frac{2}{5} * -3 + b$ , or solving for b: $b = 1-(-\frac{2}{5})(-3)$ . $b = -\frac{1}{5}$ .
(2,-1). y = mx + b or $-1=-\frac{2}{5} * 2 + b$ , or solving for b: $b = 1-(-\frac{2}{5})(2)$ . $b = -\frac{1}{5}$ .