take the improper folder to the proper place. but if that don't work if you have a copy of it then copy paste it to always be sure to have a backup
and sans said have this picture∵
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Answer:
Written in Python:
fruit_dictionary = {}
fruit_dictionary = {'apple': 'red', 'orange': 'orange', 'banana': 'yellow'}
Explanation:
First (although, not necessary), we create an empty dictionary named fruit_dictionary on line 1
Next, we populate the dictionary using the following syntax:
{key-1:value-1, key-2:value-2,......,key-n:value-n}
In this case, the entry would be:
{'apple': 'red',
'orange': 'orange',
'banana': 'yellow'}
The items on the first column (i.e. apple, orange and banana) are the keys while the items on the second (i.e. red, orange and yellow) are the values of the dictionary
To print the items in the dictionary, you can add the following line of code:
<em>print(fruit_dictionary.items()) </em>
TCP/IP is a communications protocol used to send information over the web.
Explanation:
TCP / IP, which stands for the Transmission Control Protocol / Internet Protocol, is a set of communication protocols used to connect internet network devices. The whole suite of the Internet Protocol — a set of rules and procedures — is commonly called TCP / IP.
The TCP / IP protocol suite acts as a layer of abstraction between web applications and the routing / switching fabric. TCP / IP defines how data is shared over the internet by supplying end-to-end communications that specify how the data should be split into packets, signed, distributed, routed and received at the destination.
Answer:
public class Main
{
public static void main(String[] args) {
System.out.println(min(3, -2, 7));
}
public static int min(int n1, int n2, int n3){
int smallest = Math.min(Math.min(n1, n2), n3);
return smallest;
}
}
Explanation:
*The code is in Java.
Create a method named min that takes three parameters, n1, n2, and n3
Inside the method:
Call the method Math.min() to find the smallest among n1 and n2. Then, pass the result of this method to Math.min() again with n3 to find the min among three of them and return it. Note that Math.min() returns the smallest number among two parameters.
In the main:
Call the method with parameters given in the example and print the result
