Answer:
1. 2588672 bits
2. 4308992 bits
3. The larger the data size of the cache, the larger the area of memory you will need to "search" making the access time and performance slower than the a cache with a smaller data size.
Explanation:
1. Number of bits in the first cache
Using the formula: (2^index bits) * (valid bits + tag bits + (data bits * 2^offset bits))
total bits = 2^15 (1+14+(32*2^1)) = 2588672 bits
2. Number of bits in the Cache with 16 word blocks
Using the formula: (2^index bits) * (valid bits + tag bits + (data bits * 2^offset bits))
total bits = 2^13(1 +13+(32*2^4)) = 4308992 bits
3. Caches are used to help achieve good performance with slow main memories. However, due to architectural limitations of cache, larger data size of cache are not as effective than the smaller data size. A larger cache will have a lower miss rate and a higher delay. The larger the data size of the cache, the larger the area of memory you will need to "search" making the access time and performance slower than the a cache with a smaller data size.
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Answer:
d. All of the given options
Explanation:
Great question, it is always good to ask away and get rid of any doubts that you may be having.
<u>Advertising and Publicity</u> is used for many reasons.
Retail Companies use advertising and publicity to promote their products and in term increase sales of that product when it hits the shelves.
Meanwhile, other companies such as Law Firms use advertising and publicity create awareness for their law firm and communicate with customers over high profile case etc.
Therefore, the answer is all of the above.
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