Solve the equation: 6x - 4 + 2(5x + 2) = 16x*

A manufacturer of sprinkler systems designed for fire protection claims that the average activating temperature is at least 135°

nirvana33 [79]

Answer:

$z=\frac{133-135}{\frac{3.3}{\sqrt{32}}}=-3.428$

$p_v =P(z$

If we compare the p value and the significance level given for example $\alpha=0.1$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the true mean is significantly lower than 135 so the claim not makes sense

Step-by-step explanation:

Data given and notation

$\bar X=133$ represent the sample mean

$\sigma=3.3$ represent the standard deviation for the population

$n=32$ sample size

$\mu_o =135$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to determine if the true mena is at least 135, the system of hypothesis would be:

Null hypothesis: $\mu \geq 135$

Alternative hypothesis: $\mu < 135$

We know the population deviation, so for this case is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{133-135}{\frac{3.3}{\sqrt{32}}}=-3.428$

Calculate the P-value

Since is a one-side lower test the p value would be:

$p_v =P(z$

Conclusion

If we compare the p value and the significance level given for example $\alpha=0.1$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the true mean is significantly lower than 135 so the claim not makes sense

3 0

3 years ago

Whats bigger? -6 or -5????? PLZ HELP

monitta

Answer:

-5 is more positive than -6. SO bigger, I think means less negative, so -5.

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Evaluate and simplify the following complex fraction.:6/7 ÷ 3/11

inna [77]

Answer:

3 7/50

Step-by-step explanation:

so you need them to become common denominators

a common multiple they both have would be is 77

6/7 becomes 66/77 and 3/11 becomes 21/77

now we divide

keep the 66/77 as is and flip 21/77 (keep, change, flip)

so now our equation looks like this: 66/77 x 77/21

and your answer is 3.14

but as a fraction it is 157/50 and to simplified it would be 3 7/50 (mixed fraction)

3 0

2 years ago

Lenox ironed 1/4 of the shirts over the weekend. She plans to split the remainder of the work equally over the next 5 evenings.

MrMuchimi

3/20, or 0.15 of the shirts each evening

1 - 1/4 = 3/4

(3/4) / 5 = (3/4) / (5/1) = (3/4) x (1/5) = 3/20 = 0.15

4 0

3 years ago

Read 2 more answers

Allied Corporation is trying to sell its new machines to Ajax. Allied claims that the machine will pay for itself since the time

kvasek [131]

Answer:

z(s) is in the acceptance region. We accept H₀ we did not find a significantly difference in the performance of the two machines therefore we suggest not to buy a new machine

Step-by-step explanation:

We must evaluate the differences of the means of the two machines, to do so, we will assume a CI of 95%, and as the interest is to find out if the new machine has better performance ( machine has a bigger efficiency or the new machine produces more units per unit of time than the old one) the test will be a one tail-test (to the left).

New machine

Sample mean x₁ = 25

Sample variance s₁ = 27

Sample size n₁ = 45

Old machine

Sample mean x₂ = 23

Sample variance s₂ = 7,56

Sample size n₂ = 36

Test Hypothesis:

Null hypothesis H₀ x₂ - x₁ = d = 0

Alternative hypothesis Hₐ x₂ - x₁ < 0

CI = 90 % ⇒ α = 10 % α = 0,1 z(c) = - 1,28

To calculate z(s)

z(s) = ( x₂ - x₁ ) / √s₁² / n₁ + s₂² / n₂

s₁ = 27 ⇒ s₁² = 729

n₁ = 45 ⇒ s₁² / n₁ = 16,2

s₂ = 7,56 ⇒ s₂² = 57,15

n₂ = 36 ⇒ s₂² / n₂ = 1,5876

√s₁² / n₁ + s₂² / n₂ = √ 16,2 + 1.5876 = 4,2175

z(s) = (23 - 25 )/4,2175

z(s) = - 0,4742

Comparing z(s) and z(c)

|z(s)| < | z(c)|

z(s) is in the acceptance region. We accept H₀ we did not find a significantly difference in the performance of the two machines therefore we suggest not to buy a new machine

The very hight dispersion of values s₁ = 27 is evidence of frecuent values quite far from the mean

3 0

3 years ago