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jasenka [17]
3 years ago
9

Solve the equation: 6x - 4 + 2(5x + 2) = 16x*

Mathematics
1 answer:
uysha [10]3 years ago
7 0
The answer is that there is no solution.

The problem would be 16x = 16x so there is no solution.
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Answer: I think the answer is 1011.84. Hope this helps. Can you give me brainliest

Step-by-step explanation:

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y-y=m(x-x)

-3-4=m(7-0)

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Consider the set {1, 2, 3, 4}.
Nady [450]

Answer:

(a)

List = \{(1,1),(1,2),(1,3),(1,4),(2,1),(2,2),(2,3),(2,4),(3,1),(3,2),(3,3),(3,4),\\(4,1),(4,2),(4,3).(4,4)\}

(b) Sampling Distribution (Table)

\begin{array}{cccccccc}{\bar x} & {1} & {1.5} & {2} & {2.5} & {3} & {3.5} & {4} & {Pr}& {\frac{1}{16}} & {\frac{1}{8}} & {\frac{3}{16}} & {\frac{1}{4}} & {\frac{3}{16}} & {\frac{1}{8}} & {\frac{1}{16}} \ \end{array}

(b) Sampling Distribution (Histogram)

See attachment

Step-by-step explanation:

Given

Set = \{1,2,3,4\}

n =4

Solving (a): A list of sample size 2

We have:

n =4

r = 2 --- the sample size

First, we calculate the number of list using permutation (orders matter)

n(List) = n^r

So, we have:

n(List) = 4^2

n(List) = 16

And the list is:

List = \{(1,1),(1,2),(1,3),(1,4),(2,1),(2,2),(2,3),(2,4),(3,1),(3,2),(3,3),(3,4),\\(4,1),(4,2),(4,3).(4,4)\}

Solving (b): Sample distribution  of sample means of (a)

First, calculate the mean of each set using:

Mean = \frac{Sum}{2}

So, we have:

(1,1) \to \frac{1+1}{2} \to 1       (1,2) \to \frac{1+2}{2} \to 1.5    (1,3) \to \frac{1+3}{2} \to 2    (1,4) \to \frac{1+4}{2} \to 2.5

(2,1) \to \frac{2+1}{2} \to 1.5    (2,2) \to \frac{2+2}{2} \to 2     (2,3) \to \frac{2+3}{2} \to 2.5    (2,4) \to \frac{2+4}{2} \to 3

(3,1) \to \frac{3+1}{2} \to 2       (3,2) \to \frac{3+2}{2} \to 2.5    (3,3) \to \frac{3+3}{2} \to 3    (3,4) \to \frac{3+4}{2} \to 3.5

(4,1) \to \frac{4+1}{2} \to 2.5    (4,2) \to \frac{4+2}{2} \to 3    (4,3) \to \frac{4+3}{2} \to 3.5    (4,4) \to \frac{4+4}{2} \to 4

Write out the sample means (sorted)

\bar x =\{1,1.5,1.5,2,2,2,2.5,2.5,2.5,2.5,3,3,3,3.5,3.5,4\}

Construct a frequency table

\begin{array}{cc}{\bar x} & {f} & {1} & {1} & {1.5} & {2} & {2}  & {3} & {2.5} & {4} & {3} & {3} & {3.5} &{2} & {4} & {1} & Total & 16\ \end{array}

Construct the sampling distribution where the probability is calculated using: \frac{f}{Total}

So, we have:

\begin{array}{cccccccc}{\bar x} & {1} & {1.5} & {2} & {2.5} & {3} & {3.5} & {4} & {Pr}& {\frac{1}{16}} & {\frac{1}{8}} & {\frac{3}{16}} & {\frac{1}{4}} & {\frac{3}{16}} & {\frac{1}{8}} & {\frac{1}{16}} \ \end{array}

4 0
3 years ago
Free brainliest!!!!!!!!!!!!!!!1
AlekseyPX

Step-by-step explanation:

MEEEEEEEEEEE!!!!!!!

4 0
3 years ago
Read 2 more answers
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