All categories

3 years ago

Solve the equation: 6x - 4 + 2(5x + 2) = 16x*

Mathematics

1 answer:

uysha [10]3 years ago

7 0

The answer is that there is no solution.

The problem would be 16x = 16x so there is no solution.

You might be interested in

Given the terms a10 = 3 / 512 and a15 = 3 / 16384 of a geometric sequence, find the exact value of the term a30 of the sequence.

GenaCL600 [577]

The answer is $\frac {3}{2^{29}}$

5 0

3 years ago

What is 9/20-3/20 in the simplest

stepan [7]

$\frac{9}{20}- \frac{3}{20} = \frac{6}{20}$ ÷ $\frac{2}{2} = \frac{3}{10}$

4 0

3 years ago

Read 2 more answers

How to write the slope intercept equation for points of (6,0) and (0,-5)?

Vadim26 [7]

Answer:

$y=\frac{5}{6} x -5$

Step-by-step explanation:

Hi there!

We are given the points (6,0) and (0, -5), and we want to write the equation of the line containing those points in slope-intercept form

Slope-intercept form can be written as y=mx+b, where m is the slope and b is the y intercept

First, we need to find the slope of the line

The formula for the slope can be written as $\frac{y_2-y_1}{x_2-x_1}$ , where $(x_1, y_1)$ and $(x_2, y_2)$ are points

We have everything we need to find the slope, but let's label the points to avoid confusion

$x_1=6\\y_1=0\\x_2=0\\y_2=-5$

Now substitute these values into the formula

m= $\frac{y_2-y_1}{x_2-x_1}$

m= $\frac{-5-0}{0-6}$

Subtract

m= $\frac{-5}{-6}$

Simplify

m= $\frac{5}{6}$

The slope of the line is 5/6

Let's plug this value into the formula for the equation of the line in slope-intercept form.

We substitute 5/6 for m in y=mx+b:
y= $\frac{5}{6}x+b$

Now we need to find b

As stated before, b is the y intercept, which is the value where the line hits the y axis. The value of x at the y intercept is 0.

One of the points we were given is actually the y intercept; that point is (0, -5); notice how the value of x in this point is 0

The value of b is the value of y in this point, which is -5 in this case.

Substitute -5 as b in the formula.

$y=\frac{5}{6} x -5$

Hope this helps!

See more on this subject here (n.b. the answer uses a different way of solving): brainly.com/question/20891204

8 0

2 years ago

On a coordinate plane, triangle A B C is shown. Point A is at (0, 0), point B is at (3, 4), and point C is at (3, 2). What is th

Elena L [17]

Answer:

The area of triangle for the given coordinates is 1.5 $\sqrt{4.6}$

Step-by-step explanation:

Given coordinates of triangles as

A = (0,0)

B = (3,4)

C = (3,2)

So, The measure of length AB = a = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, a = $\sqrt{(3-0)^{2}+(4-0)^{2}}$

Or, a = $\sqrt{9+16}$

Or, a = $\sqrt{25}$

∴ a = 5 unit

Similarly

The measure of length BC = b = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, b = $\sqrt{(3-3)^{2}+(2-4)^{2}}$

Or, a = $\sqrt{0+4}$

Or, b = $\sqrt{4}$

∴ b = 2 unit

And

So, The measure of length CA = c = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, c = $\sqrt{(3-0)^{2}+(2-0)^{2}}$

Or, c = $\sqrt{9+4}$

Or, c = $\sqrt{13}$

∴ c = $\sqrt{13}$ unit

Now, area of Triangle written as , from Heron's formula

A = $\sqrt{s\times (s-a)\times (s-b)\times (s-c)}$

and s = $\frac{a+b+c}{2}$

I.e s = $\frac{5+2+\sqrt{13}}{2}$

Or. s = $\frac{7+\sqrt{13}}{2}$

So, A = $\sqrt{(\frac{(7+\sqrt{13})}{2})\times ((\frac{(7+\sqrt{13})}{2})-5)\times (\frac{7+\sqrt{13}}{2}-2)\times (\frac{7+\sqrt{13}}{2}-\sqrt{13})}$

Or, A = $\sqrt{(\frac{(7+\sqrt{13})}{2})\times (\frac{(\sqrt{13}-3)}{2})\times (\frac{4+\sqrt{13}}{2})\times (\frac{7-\sqrt{13}}{2})}$

Or, A = $\frac{3}{2}$ × $\sqrt{1+\sqrt{13} }$

∴ Area of triangle = 1.5 $\sqrt{4.6}$

Hence The area of triangle for the given coordinates is 1.5 $\sqrt{4.6}$ Answer

7 0

3 years ago

Read 2 more answers

8 1/4 divided by t = 2/11<br> Answer for t

Westkost [7]

Answer:

1 1/2

Step-by-step explanation:

Turn 8 1/4 into 33/4

Then multiply 33/4*2/11 to get 66/44 then simplify to 1 1/2

4 0

2 years ago

Read 2 more answers