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Masja [62]
3 years ago
7

I'm thinking of a number. My number is 5 more than one half of my number. What's my number?

Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
7 0

Answer:

10

Step-by-step explanation:

Half of 10 is 5. 5+5 is 10

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Amiraneli [1.4K]

Answer:

Science? :)

Step-by-step explanation:

5 0
3 years ago
The area of the triangle below is 8.91 square inches. What is the length of the base?
Studentka2010 [4]

Answer:

8.1 inches

Step-by-step explanation:

Area of a triangle = ½ × base × height = Area

Rearranged =

\frac{area}{ \frac{1}{2}  \times height}

Base is the length by the way.

\frac{8.91}{ \frac{1}{2} \times 2.2 }

=8.1 inches

6 0
3 years ago
Read 2 more answers
Find the domain of the function f(x)=<img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%5E3-16x%7D" id="TexFormula1" title="\sqrt{x^3
Anon25 [30]

Answer:

Please check the explanation.

Step-by-step explanation:

Given the function

f\left(x\right)=\sqrt{x^3-16x}

We know that the domain of the function is the set of input or arguments for which the function is real and defined.  

In other words,  

  • Domain refers to all the possible sets of input values on the x-axis.

Now, determine non-negative values for radicals so that we can sort out the domain values for which the function can be defined.

x^3-16x\ge 0

as x³ - 16x ≥ 0

\left(x+4\right)\left(x-4\right)\ge \:0

Thus, identifying the intervals:

-4\le \:x\le \:0\quad \mathrm{or}\quad \:x\ge \:4

Thus,

The domain of the function f(x) is:

x\left(x+4\right)\left(x-4\right)\ge \:0\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-4\le \:x\le \:0\quad \mathrm{or}\quad \:x\ge \:4\:\\ \:\mathrm{Interval\:Notation:}&\:\left[-4,\:0\right]\cup \:[4,\:\infty \:)\end{bmatrix}

And the Least Value of the domain is -4.

3 0
3 years ago
What is the equation of the line that is perpendicular to the line through (1,-4) and (-2,2) and passes through the x-intercept
ss7ja [257]

Answer:

y=-\frac{1}{2}x+\frac{3}{2}

Step-by-step explanation:

First, calculate the slope of the line that is perpendicular to the equation of line we are asked to find

m=(y2-y1)/(x2-x1)

  =(2-(-4))/(-2-1)

  =6/-3

  =-2

in this equation the slope is 2, and to find the first equation, use y=mx+b

use the point (1, -4) to find b

-4=(2)(1)+b

-4=2+b

b=-6

the first equation of the line is y=2x-6

to find the x intercept of that line substitute 0 for y

0=2x-6

2x=6

x=3

the slope of a line perpendicular to this would be the opposite reciprocal of the slope which would be equal to -1/2

for the second equation of the line to pass thorugh the x-intercept of the first line, it must pass through (3, 0), so substitute and solve for b

y=mx+b

0=(-1/2)(3)+b

b=3/2

thus the equation of the line that is perpendicular to the line through (1,-4) and (-2, 2) and passes through the x intercept of that line is y=-\frac{1}{2}x+3/2

8 0
3 years ago
Let x be normally distributed with mean μ = 133 and standard deviation σ = 23. use table 1.
Svetlanka [38]
A) z value =  (x - π) / <span>σ   = 100 - 133 /  23  =  -1.43
p(<= 100) = 0.0764

</span>
8 0
3 years ago
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