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AVprozaik [17]
3 years ago
8

Wich is the solution for -7x > 49 ?

Mathematics
1 answer:
almond37 [142]3 years ago
4 0

Answer:

x > -7

<h2>Steps - </h2>

-7x > 49

Multiply both sides by (-1) (Reverse inequality)

(-7x) (-1) < 49 (-1)

Simplify

7x < -49

Divide both sides by 7

7x/7 < -49/7

Simplify = x > -7

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40 + 2b3 when<br> b = 5 and c= 1.2
kramer

9514 1404 393

Answer:

  254.8

Step-by-step explanation:

Substitute the numbers where the variables are and do the arithmetic.

  4c +2b³ = 4(1.2) +2(5³) = 4.8 +250 = 254.8

__

It can also work to let a calculator or spreadsheet do the math for you, once you specify the function.

8 0
2 years ago
Write a equation of a hyperbola given the foci and the asymptotes
professor190 [17]

Solution:

The standard equation of a hyperbola is expressed as

\begin{gathered} \frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1\text{ \lparen parallel to the x-axis\rparen} \\ \frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}=1\text{ \lparen parallel to the y-axis\rparen} \end{gathered}

Given that the hyperbola has its foci at (0,-15) and (0, 15), this implies that the hyperbola is parallel to the y-axis.

Thus, the equation will be expressed in the form:

\frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}=1\text{ ----equation 1}

The asymptote of n hyperbola is expressed as

y=\pm\frac{a}{b}(x-h)+k

Given that the asymptotes are

y=\frac{3}{4}x\text{ and y=-}\frac{3}{4}x

This implies that

a=3,\text{ and b=4}

To evaluate the value of h and k,

undefined

3 0
1 year ago
Annie has al metre piece of wire.
KIM [24]

Answer:

wire left for square = 100 - (14+14+4+4) cm

= (100 - 36) cm

= 64 cm

so

side of square = 64/4 = 16 cm

3 0
3 years ago
-fx-g=h solve for x​
katen-ka-za [31]

Answer:

x = -(h+g) / f

Step-by-step explanation:

-fx - g = h

-fx = h + g

x = (h + g) / -f

x = -(h+g)/f

7 0
3 years ago
Find AC if A=25°, B=24°, and CB=14
photoshop1234 [79]
Answer is 38
25+14=38
8 0
3 years ago
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