Answer:
4
Step-by-step explanation:
slope, m = (y₂ - y₁)/(x₂ - x₁)
plug in the values, and we get m = (3 - (-1))/((3 - 2) = 4
As x increases by 1, y increases by 4.
LN=8 because every time there is a midpoint you have to divide it in half. So 64,32,16,8
It is negative because the plot is going down not up
This is a linear differential equation of first order. Solve this by integrating the coefficient of the y term and then raising e to the integrated coefficient to find the integrating factor, i.e. the integrating factor for this problem is e^(6x).
<span>Multiplying both sides of the equation by the integrating factor: </span>
<span>(y')e^(6x) + 6ye^(6x) = e^(12x) </span>
<span>The left side is the derivative of ye^(6x), hence </span>
<span>d/dx[ye^(6x)] = e^(12x) </span>
<span>Integrating </span>
<span>ye^(6x) = (1/12)e^(12x) + c where c is a constant </span>
<span>y = (1/12)e^(6x) + ce^(-6x) </span>
<span>Use the initial condition y(0)=-8 to find c: </span>
<span>-8 = (1/12) + c </span>
<span>c=-97/12 </span>
<span>Hence </span>
<span>y = (1/12)e^(6x) - (97/12)e^(-6x)</span>
The air force plane travelled for a total of 6.9 hours.
<u>SOLUTION:
</u>
Given, An Air Force plane left Nairobi and flew west at an average speed of 159 mph. A cargo plane left sometime later flying in the same direction at an average speed of 207 mph. After flying for 5.3 hours the cargo plane caught up with the Air Force plane.
We have to find the number of hours the Air Force plane flew before the cargo plane caught up.
Now, we know that, 
For air force plane 
Now, when cargo plane caught the air force plane the distance travelled by the planes will be equal.
So, 
Time taken by air force plane = 6.9 hrs
