Answer:
Sample size minimum is 60
Step-by-step explanation:
given that you want to create a 99% confidence interval with a margin of error of .5.
The population standard deviation is equal to 1.5
i.e.
Confidence level = 99%
Since population std deviation is known, we can use Z critical value for finding margin of error
Z critical value for 99% = 2.58
Margin of error =
Equate this to 0.5 and solve for n
Answer:
57.5
Step-by-step explanation:
The expected frequency of West Campus and Failed :
Let :
Failed = F
East Campus = C
West Campus = W
Passed = P
Frequency of FnW :
[(FnE) + (FnW) * (PnW) + (FnW)] / total samples
[(52 + 63) * (63 + 37)] / 200
[(115 * 100)] / 200
11500 / 200
= 57.5
n(Failed n East campus)
The simplified form of given expression is
<em><u>Solution:</u></em>
Given that we have to simplify the expression
<em><u>Given expression is:</u></em>
We can simplify the expression by multiplying each term in first bracket with each term term in second bracket
Simplify the above expression by multiplying the numbers in each term and adding the coefficients of like variables in each term
Combine the like terms
Thus the expression is simplified