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egoroff_w [7]
3 years ago
9

Common multiples for 3,6 and 8​

Mathematics
1 answer:
Sindrei [870]3 years ago
4 0
24 is the common multiple *\(^o^)/*
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How are such problems done? I need a refresher on this.
Talja [164]
It would be (BASE * HEIGHT) = AREA
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7 0
3 years ago
The scale of the map is 1 inch = 12 miles. The actual distance from Liberty to West Quall is 72 miles and it is 6 inches on the
fgiga [73]
6•12= 72 4•12=48 if each inch equals 12 miles then you times the number of inches by the miles per inch
3 0
3 years ago
Can someone help me please
Anarel [89]

Answer:

Step-by-step explanation:

I made a table with a pretend number of years of teaching by picking a somewhat random number to start

"Clark has less seniority than Cornwall but more than Prendergast:"  I picked 3 for Clark 4 for Cornwall, and 2 for Prendergast, to start.

"Prendergast has more than Brown but less than Alexander:"  I see I'm running out of easy numbers here.  "Prendergast has more than Brown" means give Brown 1 year but this new teacher, Alexander needs a number between Clark and Prendergast.  To make room, I increased Clark and Cornwall by 1 and finished the remainder in the "Final Years" column:

<u>Teacher </u>     <u>Years</u>     <u> Final Years</u>

Clark         3               4

Cornwall         4               5

Prendergast                  2    

Brown                          1

Alexander                  3

The highest seniority teacher, Cornwall, is smart and refuses the job.  That leaves Clark, at number 2 seniority, to become the new supervisor.

6 0
2 years ago
Find a point on the curve x^3+y^3=11xy other than the origin at which the tangent line is horizontal.
attashe74 [19]

Compute the derivative dy/dx using the power, product, and chain rules. Given

x³ + y³ = 11xy

differentiate both sides with respect to x to get

3x² + 3y² dy/dx = 11y + 11x dy/dx

Solve for dy/dx :

(3y² - 11x) dy/dx = 11y - 3x²

dy/dx = (11y - 3x²)/(3y² - 11x)

The tangent line to the curve is horizontal when the slope dy/dx = 0; this happens when

11y - 3x² = 0

or

y = 3/11 x²

(provided that 3y² - 11x ≠ 0)

Substitute y into into the original equation:

x³ + (3/11 x²)³ = 11x (3/11 x²)

x³ + (3/11)³ x⁶ = 3x³

(3/11)³ x⁶ - 2x³ = 0

x³ ((3/11)³ x³ - 2) = 0

One (actually three) of the solutions is x = 0, which corresponds to the origin (0,0). This leaves us with

(3/11)³ x³ - 2 = 0

(3/11 x)³ - 2 = 0

(3/11 x)³ = 2

3/11 x = ³√2

x = (11•³√2)/3

Solving for y gives

y = 3/11 x²

y = 3/11 ((11•³√2)/3)²

y = (11•³√4)/3

So the only other point where the tangent line is horizontal is ((11•³√2)/3, (11•³√4)/3).

3 0
3 years ago
List all the equivalent fractions for the 12/20<br>​
8090 [49]

Answer:

6/10  

9/15  

12/20

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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