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Makovka662 [10]
3 years ago
9

12,10,15, 13.18.16.21.19 what comes next .​

Mathematics
2 answers:
Marat540 [252]3 years ago
4 0
The answer is 24:) I agree with the person above ^
shtirl [24]3 years ago
3 0
The answer is 24. it works like this. you subtract 2 from 12 and get 10. then add 5 to 10 to get 15. then subtract 2 from 15 and get 13. 13+5 is 18. and so on
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1/2r + 2 (3/4r - 1) = 1/4r + 6<br><br>​
gtnhenbr [62]

Answer:

r=32/7

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Help please............................
Vesnalui [34]

Step-by-step explanation:

csc x / (cot x + tan x)

Write in terms of sine and cosine.

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3 0
3 years ago
Multiplier method increase £88 by 14%
Morgarella [4.7K]

Answer:

if you just want 14% of 88

14% of 88 = 12.32, 0.14 * 88

if you want 14% of 88 + 88

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Step-by-step explanation:

2% of x = 0.02 * x

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6 0
3 years ago
I'd really appreciate some help on these questions, I'm really struggling
nikklg [1K]
We can use linear combinations of the equations to eliminate variables.

3x - 4y = 1
-2x + 3y = 1

To eliminate y we'll make the linear combination of 3 times the first equation minus four times the second. 

9x - 12y = 3
-8x + 12y = 4

Adding,
x = 7

We could solve for y directly but let's use another linear combination, twice the first plus three times the second:

2(3x - 4y) + 3(-2x + 3y)= 2(1)+3(1)

y = 5

Check: 3(7)-4(5)=1 good.   -2(7)+3(5)=1 good.

Q18 Answer: (7,5)

y = -3x + 5
5x - 4y = -3

4y +1(5x - 4y) = 4(-3x + 5) + 1(-3)

5x = -12x + 20 -3

17 x = 17

x = 1
y = -3(1) + 5 = 2
Check: 5(1) - 4(2) = -3 good

Q19 Answer (1,2)

6x + 5y = 25
x = 2y + 24
6x = 12y + 144
5y = 25 - 12y - 144
17y = -119
y = -119/17= -7
x = 2y+24= 10
Check: 6(10)+5(-7)=25 good   2y+24=2(-7)+24=10=x good

Q20 Answer (10,-7)


3x + y = 18
-7x + 3y = -10
9x  + 3y = 54
9x - -7x = 54 - -10
16x = 64
x=4
y = 18 -3x = 18-12=6

Check: 3(4)+6=18 good,  -7(4)+3(6)=-10 good

Q21 Answer: (4,6)

6 0
3 years ago
(1/2)^2 - 6 (2 - 2/3)<br><br> Note: 1/2 and 2/3 is a fraction
shusha [124]
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5 0
3 years ago
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