1/2r + 2 (3/4r - 1) = 1/4r + 6
2 answers:
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Answer:
(a) The probability of overbooking is 0.2135.
(b) The probability that the flight has empty seats is 0.4625.
Step-by-step explanation:
Let the random variable <em>X</em> represent the number of passengers showing up for the flight.
It is provided that a small regional carrier accepted 19 reservations for a particular flight with 17 seats.
Of the 17 seats, 14 reservations went to regular customers who will arrive for the flight.
Number of reservations = 19
Regular customers = 14
Seats available = 17 - 14 = 3
Remaining reservations, n = 19 - 14 = 5
P (A remaining passenger will arrive), <em>p</em> = 0.52
The random variable <em>X</em> thus follows a Binomial distribution with parameters <em>n</em> = 5 and <em>p</em> = 0.52.
(1)
Compute the probability of overbooking as follows:
P (Overbooking occurs) = P(More than 3 shows up for the flight)
Thus, the probability of overbooking is 0.2135.
(2)
Compute the probability that the flight has empty seats as follows:
P (The flight has empty seats) = P (Less than 3 shows up for the flight)
Thus, the probability that the flight has empty seats is 0.4625.
The ratio between the departments is
A: B: C
15000 : 18000 : 9000
15 : 18 : 9
5 : 6 : 3
The budget needs to be divided into 5+6+3 = 14 parts
The budget for one part is 22000/14
The budget for department B is
Rounded to the nearest dollar, the budget is $9429
A: B: C
15000 : 18000 : 9000
15 : 18 : 9
5 : 6 : 3
The budget needs to be divided into 5+6+3 = 14 parts
The budget for one part is 22000/14
The budget for department B is
Rounded to the nearest dollar, the budget is $9429