First we need to find the slope of the original equation
2x - 3y = 3
-3y = -2x + 3
y = 2/3x - 1....the slope here is 2/3.
However, we need a perpendicular line...so we need to use the negative reciprocal slope. All that means is flip the slope and change the sign.
slope 2/3.....flip.....3/2....change the sign...-3/2.
so our perpendicular line will need a slope of -3/2.
y = mx + b
slope(m) = -3/2
(-8,2)...x = -8 and y = 2
now we sub and solve for b, the y int
2 = -3/2(-8) + b
2 = 12 + b
2 - 12 = b
-10 = b
so our perpendicular line is : y = -3/2x - 10
Answer:
A=60
Step-by-step explanation:
Add 28+20+12
A=60
This is a geometric sequence with an initial term of 27 and a common ratio of 1/3
This just means that each term is 1/3 the term preceding it.
Any geometric sequence can be expressed as:
a(n)=ar^(n-1), a=initial term, r=common ratio, n=term number in this case:
a(n)=27(1/3)^(n-1)
Answer:
B
as [tex]\cos(\theta)=\srqt{1-\sin^2(\theta)}\[tex]
and since theta is in second quadrant, where cosine is negative,
so -√(1-z²)
