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Dmitry_Shevchenko [17]
3 years ago
7

Can you please help me

Mathematics
1 answer:
ozzi3 years ago
5 0
250 * 5= 1250 i think
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Which function has the same domain as y=2_/x?​
navik [9.2K]

Answer:

A. y = square root of 2x

We are given the function

y = 2 √x

We are asked for the function that has the same domain as the given function

First, the domain for the given function is this

{ x | x ≥ 0 }

So, any function that has a domain of x that is equal to or greater than 0. Some examples:

f(x) = √x  -  2

f(x) = 5 √x

8 0
3 years ago
Ew Mathematics i am just filling up the space
kykrilka [37]

Answer:

For starters for the angles to be complementary they have to be 90 degrees

and angle ECD is a 52 degree angle. Next, you would need to subtract 52 degrees from 90 degrees and get an answer of 38 degrees. Making DCF a 38 degree angle.

Step-by-step explanation:

7 0
2 years ago
Mr. Collins ordered 8,000 oz of stone how many tons of stone did he order? ​
padilas [110]

Answer:

0.25.

Step-by-step explanation:

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7 0
3 years ago
A cola-dispensing machine is set to dispense 8 ounces of cola per cup, with a standard deviation of 1.0 ounce. The manufacturer
pshichka [43]

Answer:

Step-by-step explanation:

Hello!

The variable of interest is X: ounces per cup dispensed by the cola-dispensing machine.

The population mean is known to be μ= 8 ounces and its standard deviation σ= 1.0 ounce. Assuming the variable has a normal distribution.

A sample of 34 cups was taken:

a. You need to calculate the Z-values corresponding to the top 5% of the distribution and the lower 5% of it. This means you have to look for both Z-values that separates two tails of 5% each from the body of the distribution:

The lower value will be:

Z_{o.o5}= -1.648

You reverse the standardization using the formula Z= \frac{X[bar]-Mu}{\frac{Sigma}{\sqrt{n} } } ~N(0;1)

-1.648= \frac{X[bar]-8}{\frac{1}{\sqrt{34} } }

X[bar]= 7.72ounces

The lower control point will be 7.72 ounces.

The upper value will be:

Z_{0.95}= 1.648

1.648= \frac{X[bar]-8}{\frac{1}{\sqrt{34} } }

X[bar]= 8.28ounces

The upper control point will be 8.82 ounces.

b. Now μ= 7.6, considering the control limits of a.

P(7.72≤X[bar]≤8.28)= P(X[bar]≤8.28)- P(X[bar]≤7.72)

P(Z≤(8.28-7.6)/(1/√34))- P(Z≤7.72-7.6)/(1/√34))

P(Z≤7.11)- P(Z≤0.70)= 1 - 0.758= 0.242

There is a 0.242 probability of the sample means being between the control limits, this means that they will be outside the limits with a probability of 1 - 0.242= 0.758, meaning that the probability of the change of population mean being detected is 0.758.

b. For this item μ= 8.7, the control limits do not change:

P(7.72≤X[bar]≤8.28)= P(X[bar]≤8.28)- P(X[bar]≤7.72)

P(Z≤(8.28-8.7)/(1/√34))- P(Z≤7.72-8.7)/(1/√34))

P(Z≤-2.45)- P(Z≤-5.71)=0.007 - 0= 0.007

There is a 0.007 probability of not detecting the mean change, which means that you can detect it with a probability of 0.993.

I hope it helps!

5 0
2 years ago
Read 2 more answers
3&lt;3x+6&lt;24<br><br>i keep getting 1 &lt; x &lt; 6<br>but the answer says -1 &lt; x &lt; 6
lara [203]
3 < 3x+6
-3<3x
-1<x

3x+6<24
3x<18
x<6

-1<x<6 the book is right

6 0
3 years ago
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