Answer:
no. nooiiiiiiiiiiiiiiiiii
If it is the letter for it then figure the equation and then fill them in
–2x<span> + 6. (</span>f<span> – </span>g)(x<span>) = </span>f<span> (</span>x<span>) – </span>g(x). = [3x + 2] – [4 – 5x]. = 3x + 2 – 4 + 5x. = 3x + 5x + 2 – 4. = 8x – 2. (f<span> × </span>g)(x) = [f<span> (</span>x)][g(x)]. = (3x + 2)(4 – 5x). = 12x + 8 – 15x2<span> – 10x ... of the </span>functions<span> at </span>x<span> = 2 and then work from there. It's probably simpler in this case to evaluate first, so: </span>f<span> (2) = 2(2) = 4. </span>g(2) = (2) + 4 = 6. h(2) = 5<span> – (2)</span>3<span> = 5 – 8 = –</span><span>3</span>
Answer:
5
Step-by-step explanation:
Using fractions:
= 
+ = 
= 5
Using decimals:
= 2.5
2.5 + 2.5 = 5
