Question

does anybody know how the answer to this looks?

Answer 1

Answer:

when x>2 (x= 3)

f(x) = -(x-2)² +1

when x = 3

f(3) = -(3-2)²+1

f(3) = -(-1)²+1

f(3) = -1+1

f(3) = 0

taking lesser value of x

makes f(x) increase

and when x>1

(x=2)

Now let's take x = 2

f(2) = -(2-2)²+1

f(2)= -(0)²+1

f(2)= 0+1 = 1

Therefore the values of x that makes f(x) = -(x-2)²+1 to increase are are (x>2 and x>1)