Answer:
The watch is cheaper in Geneva, Switzerland by a value of £20
Step-by-step explanation:
To get the city in which the watch is cheaper, what we need to do is to express the price of the watch in the same currency.
Since pounds is also used in the b part of the question, it would be easier working with it.
In Geneva, the price of the watch is 193.75 CHF
from our conversion formula;
£1 = 1.55 CHF
£x = 193.75 CHF
We cross multiply to get the value of x
(193.75 * 1)/1.55
= 193.75/1.55 = £125
We can see that the watch costs less in Geneva and higher in Manchester
By how much is it cheaper?
We can calculate this by subtracting the value in Geneva from the value in Manchester
That would be 145-125 = £20 cheaper
(0, 9) would be the coordinates of A.
Answer:
on the line
Step-by-step explanation:
Exponential functions for the following example will be given as follows:
a] <span>A town with an initial population of 2,000 doubling in size every 10 years.
solution:
The exponential function for this example will be:
f(t)=ab^(nt)
where:
a=initial size
b=growth rate
t=time
n=number of terms
thus plugging in our values we obtain:
f(t)=2000(2)^t/10
b]</span><span>A car rental that cost $20 a day plus $0.05 per mile.
This example will follow a linear equation of the form y=ax+b, where a=rate,
b=constant amount.
From our example:
a=$0.05 per mile
b=20 dollars per day
x=number of miles
Thus the function will be:
f(x)=0.05x+20
c] </span><span>A bank account with a starting balance of $1,000 compounded annually at 5%.
</span>Here we shall use the compound interest formula to obtain our value:
FV=P(1+r/100)^t
where:
FV=future value
P=principle amount
r=rate
t=time
thus, plugging in our value in the equation we obtain:
P=$1000; r=5%, time=t
f(t)=1000(1+5/100)^t
f(t)=1000(1.05)^t
Hence the function representing the case is:
f(t)=1000(1.05)^t
d] <span>A sugar processing plant producing 2 tons of sugar per month.
This will be modeled using linear function, such that the total will be given by:
f(x)=2x
where:
x is the number of months:
thus the cases that are best modeled by exponential function is:
A and C
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