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2 years ago

7

florence took a total of 12 quizzes over the course of 2 weeks. how many weeks of school will florence have to attend this quart

er before she will habe taken a total of 36 quizze?

1 answer:

nikitadnepr [17]2 years ago

6 0

Answer:

Ghhhv

Step-by-step explanation:

Thghb

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jarptica [38.1K]

Answer:

Step-by-step explanation:

21 roses are white so that is 70%

so that would be 70/100 and can reduce to 7/10

and the percent of red would be 3/10

so we can do 21 divided by 7 which equals 3

then we can do 3 x 3 because 3/10 which equals 9

then you do 21 + 9= 30

so the answer is 30.

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What % of 800,000 = 560,000

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70%

Step-by-step explanation:

560,000/800,000= 0.70

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3 years ago

Which function represents a translation of the parent cubic function 8 units to the left? h(x) = x3 + 8 h(x) = x3 – 8 h(x) = (x

Ksju [112]

Using the definition of the Vertical shifts of graphs of the function :

"Suppose c>0,

To graph y=f(x)+c, shift the graph of y=f(x) upward c units.

To graph y=f(x)-c, shift the graph of y=f(x) downward c units"

Again we recall the definition of Horizontal shifts of graphs:

" suppose c>0,

the graph y=f(x-c), shift the graph of y=f(x) to the right by c units

the graph y=f(x+c), shift the graph of y=f(x) to the left by c units. "

consider $f(x)=x^3$ is the parent function.

$h(x)=x^3+8$ shifts the graph $f(x)=x^3$ upward by 8 units

$h(x)=x^3-8$ shifts the graph $f(x)=x^3$ downward by 8 units

$h(x)=(x+8)^3$ shifts the graph $f(x)=x^3$ left by 8 units

$h(x)=(x-8)^3$ shifts the graph $f(x)=x^3$ right by 8 units.

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Part I: Measuring Parts of a Circle

cluponka [151]

Answer:

case a) The approximate circumference of circle is $5.9\ units$ and the ratio of circumference to Diameter is $\frac{C}{D}=2.95$

case b) The approximate circumference of circle is $6\ units$ and the ratio of circumference to Diameter is $\frac{C}{D}=3$

case c) The approximate circumference of circle is $6.24\ units$ and the ratio of circumference to Diameter is $\frac{C}{D}=3.12$

Step-by-step explanation:

we know that

The approximate circumference of each circle, is equal to the perimeter of each inscribed polygon

case A) the figure is an inscribed pentagon

step 1

Find the approximate circumference of circle

The perimeter of the pentagon is equal to

$P=5s$

where

$s=1.18\ units$

substitute

$P=5(1.18)=5.9\ units$

therefore

The approximate circumference of circle is $5.9\ units$

step 2

Find the ratio of circumference to Diameter

we know that

The radius is half the diameter so

$D=2r=2(1)=2\ units$

The ratio is equal to

$\frac{C}{D}=5.9/2=2.95$

case B) the figure is an inscribed hexagon

step 1

Find the approximate circumference of circle

The perimeter of the hexagon is equal to

$P=6s$

where

$s=1\ units$

substitute

$P=6(1)=6\ units$

therefore

The approximate circumference of circle is $6\ units$

step 2

Find the ratio of circumference to Diameter

we know that

The radius is half the diameter so

$D=2r=2(1)=2\ units$

The ratio is equal to

$\frac{C}{D}=6/2=3$

case C) the figure is an inscribed dodecahedron

step 1

Find the approximate circumference of circle

The perimeter of the dodecahedron is equal to

$P=12s$

where

$s=0.52\ units$

substitute

$P=12(0.52)=6.24\ units$

therefore

The approximate circumference of circle is $6.24\ units$

step 2

Find the ratio of circumference to Diameter

we know that

The radius is half the diameter so

$D=2r=2(1)=2\ units$

The ratio is equal to

$\frac{C}{D}=6.24/2=3.12$

<em>Conclusion</em>

We know that

The exact value of the ratio $\frac{C}{D}$ is equal to

$\frac{\pi D}{D}=\pi$

The approximate value of the circumference will be closer to the real one when the number of sides of the inscribed polygon is greater

4 0

3 years ago