Question

Which quadratic equation is equivalent to (x+2)^2+5(x+2)-6=0

Answer 1

Answer:

$x^2+11x+24 =0$

Step-by-step explanation:

$(x+2)^2+5(x+2)-6=0$

Substitute

$x+2 =y$

$y^2+5y-6=0\\(y+6)(y-1)=0\\y=-6,1$

Now replace y by x values

$x+2=-6\\x=-8\\x+2=-1\\x=-3$

Roots are -3 and -8

The equivalent equation would be

$(x+3)(x+8) =0\\x^2+11x+24 =0$

Answer 2

X^2 + 9x + 8 = 0

You can get this by multiplying and foiling, then simplifying.