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2 years ago

PLSSS HELP IF YOU TURLY KNOW THISS

Mathematics

1 answer:

lesantik [10]2 years ago

3 0

Answer:

x=4 hope this helps

Step-by-step explanation:

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Roughly 75% of students take the bus to school. If you were to ask 9 students in your class, what is the probability that at mos

GREYUIT [131]

The probability that at most 8 of them take the bus to school is 0.925, written in percentage form this is 92.5%

<h3>How to find the probability?</h3>

We know that roughly 75% of the students take the bus, then, if we select a student at random.

There is a probability of 0.75 that the student takes the bus.
There is a probability of 0.25 that the student does not take the bus.

The probability that at most 8 out of 9 students take the bus, is equal to one minus the probability of the 9 taking the bus, which is:

p = (0.75)^9 = 0.075

Then we have:

P = 1 - 0.075 = 0.925

The probability that at most 8 of them take the bus to school is 0.925, written in percentage form this is 92.5%

If you want to learn more about probability, you can read:

brainly.com/question/251701

3 0

2 years ago

Please write a reason for each step in solving the equation.

trapecia [35]

2. Associative property
3. is distributive property
4. Commutative property
5. Commutative property<span />

8 0

3 years ago

................................................................................................................................

Anton [14]

Answer:

what in the world is this?

3 0

1 year ago

Solve 3[-x+(2x+1)]=x-1

12345 [234]

Answer:

x = 1

Step-by-step explanation:

If you have any questions about the way I solved it, don't hesitate to ask ÷)

3 0

2 years ago

A tank contains 10 liters of pure water. Saline solution with a variable concentration 5 grams of salt per liter is pumped into

algol [13]

Answer:

dQ(t)/dt = 20 - 2Q(t)/5 , Q(0) = 0

Step-by-step explanation:

The mass flow rate dQ(t)/dt = mass flowing in - mass flowing out

Since 5 g/L of salt is pumped in at a rate of 4 L/min, the mass flow in is thus 5 g/L × 4 L/min = 20 g/min.

Let Q(t) be the mass present at any time, t. The concentration at any time ,t is thus Q(t)/volume = Q(t)/10. Since water drains at a rate of 4 L/min, the mass flow out is thus, Q(t)/10 g/L × 4 L/min = 2Q(t)/5 g/min.

So, dQ(t)/dt = mass flowing in - mass flowing out

dQ(t)/dt = 20 g/min - 2Q(t)/5 g/min

Since the salt just begins to be pumped in, the initial mass of salt in the tank is zero. So Q(0) = 0

So, the initial value problem is thus

dQ(t)/dt = 20 - 2Q(t)/5 , Q(0) = 0

3 0

2 years ago