Ask question

Ask question

All categories

2 years ago

11

THIS IS DUE IN 1 HOUR!!!! BRAINLIEST OPPORTUNITY!!!!!! PLEASE HELP!!!!! Write the radical below in simplest radical form. Decima

ls not allowed. SHOW YOUR WORK FOR BOTH OF THEM!!!!!!!! NO LINKS.
√150

√(7/2)

1 answer:

VikaD [51]2 years ago

8 0

Answer:

Square root (V) of 150:

5 V6 (5*Square root of 6)

Square Root (V) of 7/2

V14/2 (square root of 14)/2

You might be interested in

BRAINLIEST<br>through: (-3,5) parallel to y=-2x-3

umka2103 [35]

Answer:

Parallel Lines have the SAME SLOPE

We first Find the Slope of the line

y = 2 x + 3

The Slope Intercept Form of the equation of a given line is:

y = m x + c

where m is the Slope of that line, and c is the Y intercept. For this line, the Slope is 2 So the Slope of the line PARALLEL to

y = 2 x + 3

will also be 2 . And we are given that it passes through the point

( − 3 , 4 )

With this, we can use the Point Slope form to find the equation of the line.

The Point-Slope form of the Equation of a Straight Line is:

( y − k ) = m ⋅ ( x − h ) m is the Slope of the Line

( h , k ) are the co-ordinates of any point on that Line.

Here, we have been given the coordinates

( h , k ) of 1 point on that line as ( − 3 , 4 )

And the Slope m is 2

Substituting the values of h , k and m in the Point-Slope form, we get

( y − 4 ) = ( 2) ⋅ ( x − ( − 3 ) )

The above will be the Equation of the Line in Point-Slope form.

If we need it in the Slope Intercept Form, we need to follow these steps:

Modifying the equation, we get:

( y − 4 ) = 2 ⋅ ( x + 3 )

y − 4 = 2 x + 6

y = 2 x + 6 + 4

We get the equation of the line as :

y = 2 x + 10

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

What is 136 divided by 19 as a decimal

makkiz [27]

Answer:

7.157894736842105263

Step-by-step explanation:

(calculator)

3 0

2 years ago

Which table represents a linear function?

Luda [366]

A because is A jajajjajajjajajajajjajjaj

3 0

3 years ago

Simplify your answer to the previous part and enter a differential equation in terms of the dependent variable xx satisfied by x

rusak2 [61]

Answer:

x'-5x=0, or x''-25x=0, or x'''-125x=0

Step-by-step explanation:

The function $x(t)=e^{5t}$ is infinitely differentiable, so it satisfies a infinite number of differential equations. The required answer depends on your previous part, so I will describe a general procedure to obtain the equations.

Using rules of differentiation, we obtain that $x'(t)=5e^{5t}=5x \text{ then }x'-5x=0$ . Differentiate again to obtain, $x''(t)=25e^{5t}=25x=5x' \text{ then }x''-25x=0=x''-5x'$ . Repeating this process, $x'''(t)=125e^{5t}=125x=25x' \text{ then }x'''-125x=0=x'''-25x'$ .

This can repeated infinitely, so it is possible to obtain a differential equation of order n. The key is to differentiate the required number of times and write the equation in terms of x.

7 0

2 years ago

Simplify. Rewrite the expression in the form k⋅y^n. (2y^4)^3

N76 [4]

Answer:

The answer is

<h2> ${8.y}^{12}$ </h2>

Step-by-step explanation:

(2y⁴)³

Using the rules of indices

That's

<h3> $( {ax})^{b} = {a}^{b} . {x}^{b}$ </h3>

So for the above expression we have

<h3> $( {2y^{4} })^{3} = {2}^{3} . {y}^{4 \times 3}$ </h3>

Simplify

We have the final answer as

<h2>8.y¹²</h2>

Hope this helps you

5 0

3 years ago