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2 years ago

Find the perimeter of the figure to the nearest hundredth

Mathematics

1 answer:

aniked [119]2 years ago

6 0

Answer:

the perimeter of the figure to the nearest hundred is 576

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B is a subset of A g Let set A = {a, b, c} and let set B = {b, c, d} a. True b. False

xxMikexx [17]

Answer:

False

Step-by-step explanation:

A subset is a set whose elements belong to another set

If B is a subset of A, B would contain elements of A

For example, A = {a, b, c} and if B is a subset of A , B = { a, b}

7 0

3 years ago

Please HELP I NEED HELPPPPPPPPPPPPP Natasha is constructing the bisector of PQ¯¯¯¯¯. She has already constructed an arc as shown

Korvikt [17]

C is your correct answer

6 0

3 years ago

After a rotation of 90° about the origin, the coordinates of the vertices of the image of a triangle are A'(6, 3), B'(-2, 1),

Rasek [7]

Answer:

A(-3, 6), B(-1, -2), C(-7, 1)

Step-by-step explanation:

To the pre-image after a 270°-counterclockwise rotation [90°-clockwise rotation], just reverse it by doing a 270°-clockwise rotation [90°-counterclockwise rotation]:

Extended Rotation Rules

270°-clockwise rotation [90°-counterclockwise rotation] >> (x, y) → (-y, x)
270°-counterclockwise rotation [90°-clockwise rotation] >> (x, y) → (y, -x)
180°-rotation >> (x, y) → (-x, -y)

So, perform your rotation:

270°-clockwise rotation [90°-counterclockwise rotation] → C'[1, 7] was originally at C[-7, 1]

→ B'[-2, 1] was originally at B[-1, -2]

→ A'[6, 3] was originally at A[-3, 6]

I am joyous to assist you anytime.

3 0

3 years ago

Read 2 more answers

Which equation justifies why nine to the one third power equals the cube root of nine?

AVprozaik [17]

Answer:

nine to the one third power all raised to the third power equals nine raised to the one third times three power equals nine

Step-by-step explanation:

we know that

The Power of a Power Property , states that :To find a power of a power, multiply the exponents

$(a^{b})^{c}=a^{b*c}$

In this problem we have

$9^{\frac{1}{3}} =\sqrt[3]{9}$

Remember that

$\sqrt[3]{9}=9^{\frac{1}{3}}$

Raise to the third power

$[9^{\frac{1}{3}}]^3$

Applying the power of power property

$9^{\frac{3}{3}}$

$9^{1}$

$9$

therefore

nine to the one third power all raised to the third power equals nine raised to the one third times three power equals nine

8 0

3 years ago

Read 2 more answers

HELLllllllPPppppp !!!

Tasya [4]

9514 1404 393

Answer:

BC ≈ 17.0 (neither Crow nor Toad is correct)

Step-by-step explanation:

The left-side ratio of (2+4)/4 = 3/2 suggests BC is 3/2 times the length DE. If that were the case, BC = (3/2)(11) = 16.5, as Crow says.

The right-side ratio of (5+9)/9 = 14/9 suggests that BC 9 is 14/9 times the length DE. If that were the case, BC = (14/9)(11) = 154/9 = 17 1/9 ≈ 17.1, as Toad says.

The different ratios of the two sides (3/2 vs 14/9) tell you that the triangles are NOT similar, so the length of BC cannot be found by referring to the ratios of the given sides.

Rather, the Law of Cosines must be invoked, first to find angle A (109.471°), then to use that angle to compute the length of BC given the side lengths AB and AC. That computation gives BC ≈ 16.971. (See the second attachment.)

5 0

3 years ago