Its an indirect proof, so 3 steps :-
1) you start with the opposite of wat u need to prove
2) arrive at a contradiction
3) concludeReport · 29/6/2015261
since you wanto prove 'diagonals of a parallelogram bisect each other', you start wid the opposite of above statement, like below :- step1 : Since we want to prove 'diagonals of a parallelogram bisect each other', lets start by assuming the opposite, that the diagonals of parallelogram dont bisect each other.Report · 29/6/2015261
Since, we assumed that the diagonals dont bisect each other,
OC≠OA
OD≠OBReport · 29/6/2015261
Since, OC≠OA, △OAD is not congruent to △OCBReport · 29/6/2015261
∠AOD≅∠BOC as they are vertical angles,
∠OAD≅∠OCB they are alternate interior angles
AD≅BC, by definition of parallelogram
so, by AAS, △OAD is congruent to △OCBReport · 29/6/2015261
But, thats a contradiction as we have previously established that those triangles are congruentReport · 29/6/2015261
step3 :
since we arrived at a contradiction, our assumption is wrong. so, the opposite of our assumption must be correct. so diagonals of parallelogram bisect each other.
Answer:
four n squared divided by 7
Step-by-step explanation:
:) please thank me and mark me brainliest
Answer:
meema, papa, and then auntie jo
Step-by-step explanation:
you need to find the slope of each of them and then determine which one is the fastest and which one is the slowest.
meema: 48-24/4-2 = 4/2 = 2
papa: 40-24/5-3 = 16/2 = 8
auntie jo: 45-18/5-2 = 27/3 = 9
im in algebra two so you can trust my answer. happy holidays and stay safe!
