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3 years ago

Uri wants to buy a sweatshirt that

Mathematics

1 answer:

AfilCa [17]3 years ago

8 0

Answer:

Take 16.28 x 8%. You get $1.30 so add 16.28 to 1.30 to get 19.58

Step-by-step explanation:

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The giraffes roam 612 acres of grasslands and the tigers roam 346 few acres. How many acres do they roam combined?

jeyben [28]

Answer:

They roam 958 acres combined.

Step-by-step explanation:

612 + 346

= 958

4 0

2 years ago

Three fifths of the children in a school are boys. 7/8 of the girls in the school are right-handed. What fraction of the childre

Kaylis [27]

Answer:

To find the answer we only need to know,

Total no.of girls and Total no.of right handed girls.

So,

Total no.of right handed girls = 7/8

Total no.of girls = 8/8 (as given in question)

Total no.of left handed girls is,

(Fraction of total no.of girls) - (Fraction of total no.of left handed girls)

= 8/8 - 7/8

= 1/8

∴ 1/8 of the girls in the school are left handed.

7 0

3 years ago

Veronica wants to multiply

stira [4]

Answer:2737t

Step-by-step explanation:

5 0

2 years ago

PLEASE HELP ME THANKS ASAP

lara [203]

A = 28.26 units^2

Step-by-step explanation:

The formula for the area of a circle is:

$A=\pi r^2$

We can just plug in the numbers and solve.

$A=3.14*3*3$

$A=$

28.26 units^2

4 0

3 years ago

A builder wants to build the bridge whose cross section is shown in the diagram. Two companies offer simple bids on building the

leva [86]

The length of the bridge is the distance from the beginning to the end.

The distance b between each beam is 9ft.

Let:

$I \to$ I-Beam

$d_I \to$ distance between I beam and the bridge

$b \to$ distance between each I beam

Given that:

$I = \frac 34 ft\\$

$d_I = 3 ft$

$Length = 55ft\ 6in$ --- length of the bridge

From the diagram (see attachment), there are: 6 I-beams.

So, the length of the 6 I-beams is:

$L_1 = 6 \times I$

$L_1 = 6 \times \frac 34$

$L_1 = \frac {18}4$

$L_1 = 4.5ft$

There are 2 I-beams beside the bridge

So, the distance between the 2 I-beams and the bridge is:

$d_1 =2 \times d_I$

$d_1 =2 \times 3ft$

$d_1 =6ft$

There are 5 spaces between the I-beams

So, the length of the total spaces is:

$L_2 = 5 \times b$

$L_2 = 5b$

The total length is:

$Length = L_1 + d_1 + L_2$

So, we have:

$4.5ft + 6ft + 5b = 55ft\ 6in$

Collect like terms

$5b = 55ft\ 6in - 4.5ft - 6ft$

$5b = 44.5ft\ 6in$

Convert inches to feet

$5b = 44.5ft\ + \frac{6}{12}ft$

$5b = 44.5ft\ + 0.5ft$

$5b = 45ft$

Divide both sides by 5

$b = 9ft$

Hence, the distance (b) between each beam is 9ft.