Spencer would be the correct one because it's easier to keep your variables positive when trying to solve. Therefore, in order to keep the variable positive, one would have to add 4x to both sides.
Answer:The answer is choice 3
Step-by-step explanation:
Answer: Required expression: 
Result: 
Step-by-step explanation:
Given phrase: 
Required expression: ['+' used to express sum, 'x' used in place of 'of']
Since 18+16 = 34
Then,
![\dfrac14\times(18+16)=\dfrac14\times34 \\\\=\dfrac{1}{2}\times17\ \ \text{[Divide numerator and denominator by 2]}\\\\=\dfrac{17}{2}](https://tex.z-dn.net/?f=%5Cdfrac14%5Ctimes%2818%2B16%29%3D%5Cdfrac14%5Ctimes34%20%20%5C%5C%5C%5C%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes17%5C%20%5C%20%5Ctext%7B%5BDivide%20numerator%20and%20denominator%20by%202%5D%7D%5C%5C%5C%5C%3D%5Cdfrac%7B17%7D%7B2%7D)
Hence, 
An exterior angle is formed by one side of the triangle, and a side EXTENDED outside the triangle. Two angles are like that, ∠4 and ∠2.
Angle 3 is NOT an exterior angle because it is made up of two extended sides. It does not use one of the sides of the triangle.
Answer:
a=12-6b
Step-by-step explanation:
move b and a to their respective sides, getting a = -6b+12
tada :)
