Answer:

Step-by-step explanation:
An equation in the vertex form is written as

Where the point (h, k) is the vertex of the equation.
For an equation in the form
the x coordinate of the vertex is defined as

In this case we have the equation
.
Where

Then the x coordinate of the vertex is:

The y coordinate of the vertex is replacing the value of
in the function

Then the vertex is:

Therefore The encuacion excrita in the form of vertice is:

To find the coefficient a we substitute a point that belongs to the function 
The point (0, -1) belongs to the function. Thus.


<em>Then the written function in the form of vertice is</em>

Well first lets review the information on these numbers. A negative number is less than 0. So the bigger the negative number, the smaller it actually is.
So...
a) -11.6 > 7.52 (A negative is not greater than a positive!)
b) -5.39 > -4.21 (The bigger the negative the smaller the number -Nope!)
c) 8.7 < 8.63 (Nope- you can tell just by knowing the common number)
d) -6.29 < -4.81 (YES!!)
hope that helps!
Answer:
Step-by-step explanation:
to compare them, we need to convert them into like fractions
4/3 and 5/2
lcm of 3 and 2 is 6
4/3 × 2/2 = 8/6
5/2 × 3/3 = 15/6
15/6 is greater than 8/6
<em><u>so 5/2 is greater than 4/3</u></em>
similarly,
-3/2 and -4/5
we need to convert them into like fractions
lcm of 2 and 5 is 10
-3/2 × 5/5 = -15/10
-4/5 × 2/2 = -8/10
-8/10 is greater than -15/10
<u><em>so -4/5 is greater than -3/2</em></u>
Hope this helps
plz mark as brainliest!!!!
Let's assume
the number of hours Susan jogs at the increased speed is 't' hours
Since, increased speed is 6 miles per hour
after 't' hours , she travles with increased speed is 6*t miles
She starts off with a half-hour walk at a pace of 2 miles per hour
so, she travels distance
=0.5*2 miles
=1 miles
She travels a total of 4 miles
total distance is
=6t+1
now, we can set them equal

now, we can solve for t
Subtract both sides by 1


Divide both sides by 6
we get

so, the number of hours Susan jogs at the increased speed is 0.5 hrs.........Answer
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<em>Hey, love!</em>
<em>This questions seems to require some type of visual or video. It might help if you go check out what your teacher gave you with this and then come back!</em>
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