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3 years ago

11

I need help to find the Area

2 answers:

Alenkinab [10]3 years ago

8 0

The answer is 58.4 or at least in the 50s

hram777 [196]3 years ago

6 0

To find the area you have to (13.2x18)+(4x4)

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Helpp this is due in 30 minutesss

Aleonysh [2.5K]

Answer:0,2,4,6,8

Step-by-step explanation: the pounds and price rise at equal amount

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3 years ago

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Select the two values of x that are roots of this equation 2x-3=-5x^2

zvonat [6]

$\bold{Answer}$

$\boxed{\bold{X \ = \ -1, \ X \ = \ \frac{3}{5} }}$

$\bold{Explanation}$

$\bold{Find \ Two \ Values \ Of \ X: \ 2x-3=-5x^2}$

$\bold{-------------------}$

$\bold{Switch \ Sides}$

$\bold{-5x^2=2x-3}$

$\bold{Add \ 3 \ To \ Both \ Sides}$

$\bold{-5x^2+3=2x-3+3}$

$\bold{Simplify}$

$\bold{-5x^2+3=2x}$

$\bold{Subtract \ 2x \ From \ Both \ Sides}$

$\bold{-5x^2+3-2x=2x-2x}$

$\bold{Simplify}$

$\bold{-5x^2-2x+3=0}$

$\bold{Solve \ With \ The \ Quadratic \ Formula}$
$\bold{For \ The \ Quadratic \ Form \ For \ ax^2+bx+c=0 \ The \ Solutions \ Are \ x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}}$
$\bold{For \ A \ =-5,\:b=-2,\:c=3:\quad x_{1,\:2}=\frac{-\left(-2\right)\pm \sqrt{\left(-2\right)^2-4\left(-5\right)3}}{2\left(-5\right)}}$

$\bold{\frac{-\left(-2\right)+\sqrt{\left(-2\right)^2-4\left(-5\right)\cdot \:3}}{2\left(-5\right)}: \ -1}$

$\bold{\frac{-\left(-2\right)-\sqrt{\left(-2\right)^2-4\left(-5\right)\cdot \:3}}{2\left(-5\right)}: \ \frac{3}{5} }$

$\bold{Solutions}$

$\bold{x=-1,\:x=\frac{3}{5}}$

$\boxed{\bold{Eclipsed}}$

3 0

3 years ago

Brainliest to correct quick

brilliants [131]

The sign is (=)

1/2 = 0.5

So the answer is

13 1/2 = 13.5

3 0

3 years ago

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1 3/8 + 3 2/8 =<br><br> pls help me i have been on this for way to long

andrew11 [14]

Answer:

4.625

Step-by-step explanation:

4.625 Your welcome :)

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3 years ago

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vladimir2022 [97]

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4 0

3 years ago